Chemistry NCERT Exemplar Solutions Class 12th Chapter One

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Payal Gupta

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47. Option (ii) The correct order of the packing efficiency is fcc > bcc > simple cubic

Packing Efficiency (fcc) - 74% 

Packing Efficiency (bcc) - 68% 

Packing Efficiency (simple cubic) - 52% 

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Payal Gupta

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46. Option (i) all the domains get oriented in the direction of magnetic field is correct since whenever a ferromagnetic substance is placed in a magnetic field it becomes a permanent magnet as all the domains get oriented in the directions of the magnetic field even after removal of  the applied magnetic field.

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Payal Gupta

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45. Option (iv) The fraction of octahedral or tetrahedral voids occupied depends upon the radii of the ions occupying the voids is not true since the occupation of the voids depends upon the stoichiometry of the compound instead of the radii of the ions. 

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Payal Gupta

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44. Option (ii) Ferromagnetic substances cannot be magnetised permanently is correct since ferromagnetic substances are those which are very strongly attracted by the magnetic field and can be magnetized permanently.

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Payal Gupta

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43. Option (ii) n-type semiconductor is correct since silicon is doped with electron rich impurities like Phosphorus or Arsenic and this leads to the increase in the conductivity due to the negatively charged electron . Hence, silicon doped with electron rich impurity is termed as n -type semiconductor. 

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Payal Gupta

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42. Option (iv) Electronic defects is correct since doping can be done with an impurity which is electron rich or electron deficient as compared to the intrinsic semiconductor like Si or Ge . Such impurities lead to the electronic defects in them. 

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Payal Gupta

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41. Option (iii) 4 is correct since in  2-D scope structure each sphere is in contact with four of its neighbours. Thus, its coordination number is found to be 4. 

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Payal Gupta

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40. Option (i) Cl-ion form fcc lattice and Na+ ions occupy all octahedral voids of the unit cell is correct since In NaCl,  chloride ion form fcc lattice and sodium ions occupy all the octahedral voids of the unit cell. The coordination number of both the cation and anion is found to be 6.

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Payal Gupta

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39. Option (iv) since in this arrangement the spheres of fourth layer are exactly aligned with those of the first layer is correct since in hexagonal close packed structure there is ABAB.type arrangement which means that in this case spheres of third layer are exactly aligned with that of the first layer. Hence, the pattern of spheres is repeated in alternate layers. Thus, the statement at (iv) is not true about hexagonal close packing. 

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Payal Gupta

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38. Option (iii) 32 is correct  since the packing efficiency in bcc arrangement is 68%, therefore the percentage empty space  can be calculated as – 100 - 68 = 32 

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