Chemistry NCERT Exemplar Solutions Class 12th Chapter One
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4 months agoContributor-Level 10
8. Yellow colour in NaCl is due to the defect called as metal excess defect. In this defect anionic vacancies get created due to the diffusion of Cl-ions to the surface of the crystal and there after unpaired electrons occupy anionic sites. These sites are known as F-centres. The electrons at F-centres then absorb energy from the visible region and undergo excitation which makes the crystal appear yellow.
New answer posted
4 months agoContributor-Level 10
7. Crystals have long range ordered arrangement of their constituent particles but usually these crystals are not perfect as during the process of crystallisation some deviations as compared to such ideal arrangement set in depending upon the rate of cooling or presence of impurities in solution also this process occurs at such a rate that the constituent particles may not get the sufficient time to arrange themselves in a perfect order and hence these deviations or irregularities in arrangement is being termed as defects or imperfections. Therefore, crystals are usually not perfect.
New answer posted
4 months agoContributor-Level 10
6. In solids the constituent particles are found to possess fixed positions and can only oscillate about their mean positions and hence they are said to be incompressible and rigid.
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4 months agoContributor-Level 10
5. The liquids and gases both are categorised as fluids as they show the ability to flow and also their molecules can move past one another freely.
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4 months agoContributor-Level 10
4. Let the formula of sample be (Fe2+)x (Fe3+) yO
From the formula of the compound the equation can be formed as-
x+ y= 0.93 . (i)
Total positive charge on ferrous and ferric ions should balance the two units of negative charge on oxygen. Hence,
2x+ 3y= 2 . (ii)
⇒ x+ y=1. (iii)
On subtracting equation (i) from equation (iii) we have
y-y=1 - 0.93
12y=0.07
y= 0.14
On putting the value of y in equation (i)
we get, x+ 0.14 = 0.93
⇒x = 0.93 – 0.14
⇒x = 0.79
Fraction of Fe2+ ions present in the sample is = 0.81
Metal deficiency defect is found to be present in the sample
New answer posted
4 months agoContributor-Level 10
3. The conductivity of a semiconductor is very low and it can be increased by adding small impurities and this process is known as doping.
Doping can be done with an impurity which is electron rich or electron deficient-
n-type semiconductors- Si or Ge (group-14 elements) are doped with electron rich impurity (group-15 elements like P or As) and are known as n-type semiconductors. In them the conductivity is due to the extra electron or delocalized electron.
When intrinsic semiconductors like Si or Ge are doped with pentavalent elements like P or As, they occupy some of the lattice sites in silicon or germaniu
New answer posted
4 months agoContributor-Level 10
2. A ccp structure unit cell is divided into 8 small cubes. Each small cube has atoms at alternate corners as shown in the figure. In all, each small cube has 4 atoms. When these are joined to one another, they make a regular tetrahedron. Thus, there is one tetrahedral void in each small cube and 8 tetrahedral voids in total. Each of the eight small cubes has one void in one unit cell of ccp structure. We know that ccp structure has four atoms per unit cell. Thus, the number of tetrahedral voids is twice the number of atoms.

New answer posted
4 months agoContributor-Level 10
1. When any atom is surrounded by six atoms it creates an octahedral void. In fcc, body centre is surrounded by six atoms present at the face centre. And hence one octahedral void is present at the body centre of each unit cell.
No. of octahedral void at the centre of 12 edge = 12 * = 3
No. of octahedral void at body centre = 1
Total no. of octahedral void in ccp = 3+1+4

Location of octahedral voids per unit cell of ccp or fcc lattice (a) at body centre of the cube and (b) at the centre of each edge (only one such void is shown)
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