Chemistry NCERT Exemplar Solutions Class 12th Chapter Two

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Vishal Baghel

Contributor-Level 10

Hl? 12H2+12l2

t = eq1 - α2 α2 [α=0.4]

Kp= (PH2)12* (Pl2)12PHl= (0.2)12* (0.2)120.6

8.31*300*2.3*log (13)=2735J/mol

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Vishal Baghel

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π = i * c * R * T = 2 * 0 . 8 3 * 3 0 0 6 0 * 1 0 3 = 0 . 0 0 4 1 5 b a r

= 415 Pa

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Vishal Baghel

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Vapourisation of H2O, H2O (l)H2O (g)

Mole of H2O= 3618=2mol

ΔE=ΔHΔnRT

=41.11*8.31*3731000=38kJ/mole

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Vishal Baghel

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Water has only two lone pair and XeF4 has two lone pair electron in opposite plane of the central atom.

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Vishal Baghel

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After removal A = 4  (12*2)=3

After removal B = 4 – 1 = 4 (only two atoms are removed)

Final formula of the compound = A3B4

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Vishal Baghel

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 CH4+2O2CO2+2H2O

Mole 1001620832

6.256.5 (HereO2isthelimitingreagent)

Hence mole of CO2 formed = 6.52

And wt of CO2  in gm = 6.52*44=143g

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Vishal Baghel

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Vitamin B12 is not water soluble chemical.

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Vishal Baghel

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CH3 – (CH2)16 – COONa is the sodium salt of fatty acid used in soap is not synthetic detergent.

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Vishal Baghel

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Kindly consider the following figure

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Vishal Baghel

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p- toluenesulphonyl chloride

Only gives soluble product with alkali for 1° amine and for 2°- amine it gives insoluble product.

 

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