Tags Chemistry NCERT Exemplar Solutions Class 12th Chapter Two

Chemistry NCERT Exemplar Solutions Class 12th Chapter Two

Get insights from 140 questions on Chemistry NCERT Exemplar Solutions Class 12th Chapter Two, answered by students, alumni, and experts. You may also ask and answer any question you like about Chemistry NCERT Exemplar Solutions Class 12th Chapter Two

Follow Ask Question

140

Questions

Discussions

Active Users

Followers

New answer posted

2 months ago

Chemistry NCERT Exemplar Solutions Class 12th Chapter Two Amines

Reaction of [Co(H₂O)₆]²⁺ with excess ammonia and in the presence of oxygen results into a diamagnetic product. Number of electrons present in t_2g-orbitals of the product is_________.

0 Follower 3 Views

Vishal Baghel

Contributor-Level 10

${[C o {(H_{2} O)}_{6}]}^{2 +} + N H_{3 (e x c e s s)} \to \underset{D i a m a g n e t i c n a t u r e}{{[C o {(N H_{3})}_{6}]}^{3 +} + 6 H_{2} O}$

$C o^{3 +} \to 3 d^{6} 4 s^{0}$

$\Rightarrow {t_{2 g}}^{6} e g^{0}$ (form of paired electron)

No. of electron in t_2g = 6

0 0

New answer posted

2 months ago

Chemistry NCERT Exemplar Solutions Class 12th Chapter Two Class 12th

Catalyst A reduces the activation energy for a reaction by 10 kJ mol^-1 at 300K. The ratio of rate constants, $\frac{k_{T}, C a t a l y s e d}{k_{T}, U n c a t a l y s e d} i s e^{x} .$ The value of x is_________. (nearest integer)

[Assume that the pre-exponential factor is same in both the cases. Given R = 8.31 JK^-1 mol^-1]

0 Follower 2 Views

Vishal Baghel

Contributor-Level 10

$K_{c a t} = A e^{-} \frac{{(E a)}_{c a t}}{R T} a n d K_{u n c a t} = A e^{-} \frac{{(E a)}_{u n c a t}}{R T}$

$\frac{K_{c a t}}{K_{u n c a t}} = e^{\frac{{(E a)}_{u n c a t} - {(E a)}_{c a t}}{R T}} = e^{\frac{10 * 1000}{8.314 * 300}} = e^{4.009} = e^{x}$

$∴ x = 4$

0 0

New answer posted

2 months ago

Chemistry NCERT Exemplar Solutions Class 12th Chapter Two Haloalkanes and Haloarenes

Cu(s) + Sn²⁺(0.001M) ® Cu²⁺ (0.01M) + Sn(s)

The Gibbs free energy change for the above reaction at 298 K is x * 10^-1 KJmol^-1. The value of x is __________. (nearest integer)

[Given : $E_{C u^{2 +} / C u}^{Θ}$ 0.34V; $E_{S n^{2 +} / S n}^{Θ}$ =96500 Cmol^-1]

0 Follower 2 Views

Vishal Baghel

Contributor-Level 10

cell reaction is ;

$C u (s) + S n_{(a q)}^{2 +} \to C u_{(a q)}^{+ +} + S n_{(s)}$

$Q = \frac{[C u^{+ +}]}{[S n^{+ +}]} = \frac{0.01}{0.001} a n d n = 2$

$E_{c e l l} = E_{c e l l}^{o} - \frac{0.059}{2} l o g \frac{0.01}{0.001}$

$= - 0.48 - \frac{0.059}{2} l o g 10 = - 0.509$

$= 983.33 * 1 0^{- 1} K J / m o l e$

the nearest integer = 983

0 0

New answer posted

2 months ago

Chemistry NCERT Exemplar Solutions Class 12th Chapter Two Chemical Kinetics

40% of HI undergoes decomposition to H₂ and I₂ at 300K. $Δ G^{Θ}$ for this decomposition reaction at one atmosphere pressure is_____________J mol^-1 (nearest integer)

(Use R = 8.31 JK^-1 mol^-1; log 2= 0.3010, In 10 = 2.3, log 3 = 0.477)

0 Follower 3 Views

Vishal Baghel

Contributor-Level 10

$H l ? \frac{1}{2} H_{2} + \frac{1}{2} l_{2}$

t = eq1 - $\frac{α}{2}$ $\frac{α}{2} [α = 0.4]$

$K p = \frac{{(P_{H_{2}})}^{\frac{1}{2}} * {(P_{l_{2}})}^{\frac{1}{2}}}{P_{H l}} = \frac{{(0.2)}^{\frac{1}{2}} * {(0.2)}^{\frac{1}{2}}}{0.6}$

= $- 8.31 * 300 * 2.3 * l o g (\frac{1}{3}) = 2735 J / m o l$

0 0

New answer posted

2 months ago

Chemistry NCERT Exemplar Solutions Class 12th Chapter Two Solutions

The osmotic pressure exerted by a solution prepared by dissolving 2.0g of protein of molar mass 60 kg mol^-1 in 200 mL of water at 27°C is_______Pa. (nearest integer)

(Use R = 0.083 L bar mol^-1 K^-1)

0 Follower 3 Views

Vishal Baghel

Contributor-Level 10

$π = i * c * R * T = \frac{2 * 0.83 * 300}{60 * 1 0^{3}} = 0.00415 b a r$

= 415 Pa

0 0

New answer posted

2 months ago

Chemistry NCERT Exemplar Solutions Class 12th Chapter Two Class 12th

A fish swimming in water body when taken out from the water body is covered with a film of water of weight 36g. When it is subjected to cooking at 100°C, then the internal energy for vaporization in kJ mol^-1 is_____________. (nearest integer)

[Assume steam to be an ideal gas. Given $Δ_{v a p} H^{Θ}$ for water at 373K and 1 bar is 41.1 kJ mol^-1; R = 8.31 JK^-1mol^-1]

0 Follower 3 Views

Vishal Baghel

Contributor-Level 10

Vapourisation of $H_{2} O, H_{2} O_{(l)} \to H_{2} O_{(g)}$

Mole of H₂O= $\frac{36}{18} = 2 m o l$

$Δ E = Δ H - Δ n R T$

$= 41.1 - \frac{1 * 8.31 * 373}{1000} = 38 k J / m o l e$

0 0

New answer posted

2 months ago

Chemistry NCERT Exemplar Solutions Class 12th Chapter Two Thermodynamics

Amongst SF₄, XeF₄, CF₄ and H₂O, the number of species with two lone pairs of electrons is___________.

0 Follower 2 Views

Vishal Baghel

Contributor-Level 10

Water has only two lone pair and XeF₄ has two lone pair electron in opposite plane of the central atom.

0 0

New answer posted

2 months ago

Chemistry NCERT Exemplar Solutions Class 12th Chapter Two States of Matter

In a solid AB, A atoms are in ccp arrangement and B atoms occupy all octahedral sites. If two atoms from the opposite face are removed, then the resultant stoichiometry of the compound is A_xB_y. The value of x is ___________(nearest integer)

0 Follower 1 View

Vishal Baghel

Contributor-Level 10

After removal A = 4 $(\frac{1}{2} * 2) = 3$

After removal B = 4 – 1 = 4 (only two atoms are removed)

Final formula of the compound = A₃B₄

0 0

New answer posted

2 months ago

Chemistry NCERT Exemplar Solutions Class 12th Chapter Two Some Basic Concepts of Chemistry

CNG is an important transportation fuel. When 100g CNG is mixed with 208g oxygen in vechicles, it leads to the formation of CO₂ and H₂O and produces large quantity of heat during this combustion, then the amount of carbon dioxide produced in germs is ______.

(nearest integer)

[Assume CNG to be methane]

0 Follower 4 Views

Vishal Baghel

Contributor-Level 10

$C H_{4} + 2 O_{2} \to C O_{2} + 2 H_{2} O$

Mole $\frac{100}{16} \frac{208}{32}$

$\begin{array}{l} ↓ ↓ \\ 6.25 6.5 (H e r e O_{2} i s t h e l i m i t i n g r e a g e n t) \end{array}$

Hence mole of CO₂ formed = $\frac{6.5}{2}$

And wt of CO₂ in gm = $\frac{6.5}{2} * 44 = 143 g$

0 0

New answer posted

2 months ago

Chemistry NCERT Exemplar Solutions Class 12th Chapter Two Electrochemistry

Which of the following is a water soluble vitamin, that is not excreted easily?

0 Follower 1 View

Vishal Baghel

Contributor-Level 10

Vitamin B₁₂ is not water soluble chemical.

0 0

Get authentic answers from experts, students and alumni that you won't find anywhere else

On Shiksha, get access to

65k Colleges
1.2k Exams
687k Reviews
1800k Answers

Community GuidelinesUser Points System

QuestionsDiscussionsTags

Need guidance on career and education? Ask our experts

Your Question

Chemistry NCERT Exemplar Solutions Class 12th Chapter Two

Questions

Discussions

Active Users

Followers

All

Discussions

Unanswered Questions

Share Your College Life Experience