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Solutions Class 12th

What is the weightage of Class 12 Chapter 1 Solutions in CBSE and other competitive exams?

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nitesh singh

Contributor-Level 10

After the 2023-24 revised CBSE syllabus, many chapters have been removed, and in some chapters syllabus is reduced. As per the latest CBSE exam pattern 2025-26, the Chapter 1 Solutions will be asked for 5-7 marks in the Class 12 Chemistry CBSE board exams.

For other competitive exams, the Solutions chapter has a medium weightage in the NEET exam. In the NEET exam, 1-2 questions are frequently asked based on the concept of moderate-level numerical.

Physical Chemistry holds over 30% weightage in the chemistry section in the JEE Mains exam. The solutions chapter is considered a part of physical chemistry. You can expect 1 question fo

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Yesterday

Solutions Ncert Solutions Chemistry Class 12th

What are the benefits of using Class 12 Chemistry Chapter 1 NCERT Solutions?

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Esha Garg

Beginner-Level 5

NCERT offers the foundation for every class 12 student. CBSE board exam questions are primarily based on the NCERT exercise, Examples and conceptual explanation.

There are various benefits of using NCERT Solutions.

Specially for CBSE Board students, these NCERT Solutions are the best resource to prepare for the boards.
These NCERT Solutions include step-wise descriptive answer approach that will help you write good answers.
These solutions also help you understand problem-solving and how to approach a specific type of conceptual or numerical problem.
If you are preparing for the JEE or NEEt exam, these solutions can be your first deci

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Yesterday

Solutions Class 12-science

Why you should use Shiksha's NCERT Solutions for Chapter 1 Solutions Class 12 Chemistry?

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Satyendra Dhyani

Beginner-Level 5

Shiksha focuses on completely fulfilling the needs of CBSE class 12 board students. We provide NCERT Solutions for classes 11th and 12th in class for physics, chemistry and mathematics.

Here are the key reasons why you should use Shiksha's NCERT Solutions for the Solution Chapter:

Complete coverage of NCERT Exercise, including MCQs, very short, short and long answer type questions.
Step-by-step solutions according to the CBSE board exam needs.
Intext question and answer with a free downloadable PDF
complete study material for the chapter
- NCERT Chapter 1 Solutions Notes
- Solutions Quick Revision Notes
- Important Questions for Solution

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New answer posted

a week ago

Solutions Class 12th

If vapour pressure of two liquids A and B in pure state are 400 and 500 mm of Hg respectively then mole fraction of A in vapour phase of solution obtained by mixing equal moles of A and B is

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alok kumar singh

Contributor-Level 10

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New answer posted

a week ago

Solutions Chemistry Solutions

What are hypertonic and hypotonic solutions?

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Swayam Gupta

Contributor-Level 6

If a solution containing more than 0.9% salt is used, and we place blood cells in it, the water will flow out of the cells, and they will shrink. Such a solution is a hypertonic solution.

Similarly, if a solution contains less than 0.9% salt, the water will flow into the cells, and they will enlarge.

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a week ago

Solutions Chemistry Solutions

What is an unsaturated solution?

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Swayam Gupta

Contributor-Level 6

When more solute can be dissolved in a solution at a constant temperature, it is an unsaturated solution.

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a week ago

Solutions Chemistry Solutions

What is a saturated solution?

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Swayam Gupta

Contributor-Level 6

When no more solute can be dissolved in a solution at a constant temperature and pressure, it is called a saturated solution.

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a week ago

Solutions Class 12th

If vapour pressure of two liquids A and B in pure state are 400 and 500 mm of Hg respectively then mole fraction of A in vapour phase of solution obtained by mixing equal moles of A and B is

0 Follower 2 Views

alok kumar singh

Contributor-Level 10

Y_A = p_a/p_a+ p_b= 400 x ½ / 400 x ½ + 500 x ½ = 4/9

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New answer posted

2 weeks ago

Solutions Class 12th

When 12.2g of benzoic acid is dissolved in 100g of water, the freezing point of solution was found to be -0.93°C $[K_{f} (H_{2} O = 1.86 K k g m o l^{- 1}] .$ The number (n) of benzoic acid molecules associated (assuming 100% association) is…………,

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alok kumar singh

Contributor-Level 10

$Δ T_{f} = K_{f} * m * i$

0.93 = 1.86 * 1 * i

i = $\frac{1}{2}$

$i = 1 + (\frac{1}{n} - 1)$

$∴ n = 2$

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New answer posted

2 weeks ago

Solutions Class 12th

Elevation in boiling point for 1.5 molal solution of glucose in water is 4 K. The depression in freezing point for 4.5 molal solution of glucose in water is 4K. The ratio of molal elevation constant to molal depression constant (K_b/K_f) is________.

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Vishal Baghel

Contributor-Level 10

$Δ T_{b} = i K_{b} m$

$Δ T_{f} = i K_{f} m$

$∴ \frac{4}{4} = \frac{K_{b} * 1.5}{K_{f} * 4.5}$

$\frac{K_{b}}{K_{f}} = 3$

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