Chemistry NCERT Exemplar Solutions Class 12th Chapter Two
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New answer posted
10 months agoContributor-Level 10
Mole fraction of A in liquid phase, xA = 0.3
Mole fraction of B in liquid phase, xB = 0.7
Now;
= 100 * 0.7 = 70 torr
Mole fraction of B in vapour phase,
X = 14
New answer posted
10 months agoNew answer posted
10 months agoContributor-Level 10
According to Henry's law
P = KH * mole fraction of solute
Mole of O2 = 1.09 * 10-3
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