Chemistry

(E_a)_net = $E_{a_1}$ + $E_{a_2}$ – $E_{a_3}$  

= 40 + 50 – 60

= 90 – 60

= 30kJ/mol

Assume mass of solution

= 100g

Mass of solute = 36gm

Moles of solute = 1

Molarity=  $\frac{1*1000}{\left(\frac{100}{1.5}\right)}=\frac{1000}{100}*1.5=15$

₃₇Rb = 1s² 2s² 2p⁶ 3s² 3p⁶ 3d¹⁰ 4s² 4p⁶ 5s¹

Last electron enters in 5s subshell

Value of quantum numbers

n = 5, l = 0, m = 0, s =  $\pm \frac{1}{2}$

After balancing change in oxidation state,

2Cl₂ $\stackrel{}{\to }$ 2Cl^– + 2ClO^–

Next, balance 'O' atoms,

2Cl₂ +4OH^– $\stackrel{}{\to }$  2Cl^– + 2ClO^–+ 2H₂O

Simplifying to get the simplest ratios,

Cl₂ +2OH^– $\stackrel{}{\to }$ Cl^–+ClO^–+ H₂O

x = 1, y = 2, z = 1, p = 1

K₂Cr₂O₇ + H₂O₂ + H₂SO₄->  + K₂SO₄ + H₂O compound 'X' is ->CrO₅

Oxidation state of chromium = +6.

A. Vitamin B₁₂– Co

B.  Wilkinson catalyst –Rh ( [Rh (PPh₃)₃Cl])

C.  Ziegler-Natta catalyst –Ti (TiCl₄ +Al (C₂H₅)₃)

D.  Haemoglobin – Fe

Ionisation enthalpy increases in a period. Z dominates over screening effect (s) in a period as Z_eff. increases.

Proteins on hydrolysis gives α-amino acid because α-amino acids are building block of proteins. It is also fact that amino acids contain both –NH₂ and –COOH group.