Chemistry

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A
alok kumar singh

Contributor-Level 10

K2Cr2O7 + H2O2 + H2SO4->  + K2SO4 + H2O compound 'X' is ->CrO5

Oxidation state of chromium = +6.

 

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4 months ago

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A
alok kumar singh

Contributor-Level 10

A. Vitamin B12– Co

B.  Wilkinson catalyst –Rh ( [Rh (PPh3)3Cl])

C.  Ziegler-Natta catalyst –Ti (TiCl4 +Al (C2H5)3)

D.  Haemoglobin – Fe

New answer posted

4 months ago

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A
alok kumar singh

Contributor-Level 10

Kindly go through the solution

 

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alok kumar singh

Contributor-Level 10

Ionisation enthalpy increases in a period. Z dominates over screening effect (s) in a period as Zeff. increases.

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alok kumar singh

Contributor-Level 10

Proteins on hydrolysis gives α-amino acid because α-amino acids are building block of proteins. It is also fact that amino acids contain both –NH2 and –COOH group.

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alok kumar singh

Contributor-Level 10

Electronegativity generally decreases as we move down the group but Pb has higher electronegativity than Sn.

C non-metal

Si and Ge->metalloids

Sn and Pb->metals

E.N. of Sn 1.8, Pb = 1.9

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S
Satyendra Dhyani

Beginner-Level 5

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alok kumar singh

Contributor-Level 10

Na+ C + N + S ®NaSCN

Fe3+ + SCN [ F e ( S C N ) ] 2 + B l o o d r e d

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4 months ago

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alok kumar singh

Contributor-Level 10

(A) Fluorspar                     –    CaF2

(B) Cryolite                 –    Na3 [AlF6]

(C) Bauxite                 –    Al2O3.2H2O

(D) Dolomite              –    MgCO3.CaCO3

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alok kumar singh

Contributor-Level 10

p H 2 = P T χ H 2  (PT = total pressure)

χ H 2 = mole fraction of H2)

p O 2 = P T χ O 2 ( χ O 2  = mole fraction of O2)

p H 2 p O 2 = χ H 2 χ O 2 = n H 2 n O 2

n H 2 = 1 2  mol

n O 2 = 1 3 2
p H 2 p O 2 = 1 2 * 1 = 3 2

p H 2 p O 2 = 3 2 2 = 1 6 1

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