Chemistry

Acidic order

Simple concept of conjugate base stability

Cu, Zn, Ni

Composition of german silver [Cu-50%, Zn-20%, Zi-30%]

NaCN converted into HCN and Na₂S converted into H₂S

$\begin{array}{l}NaCN+HN{O}_3\to NaN{O}_3+HCN\\ N{a}_{2}S+2HN{O}_3\to NaN{O}_3+H_{2}S\end{array}$

Bond dissociation enthalpy is the energy required to break 1 mole of bond according to experimental data

Bond energy : Cl₂ > Br₂ > F₂ > l₂

Primary amine, whether aliphatic or aromatic when warmed with CHCl₃, alcoholic (KOH) it forms isocyanide

Please find the below image

I > III > IV > II

${\left[Fe{F}_6\right]}^{3-}\to F{e}^{3+}-3d^5-$ all are unpaired (n = 5)

${\left[Co{\left(N{H}_3\right)}_6\right]}^{3+}\to C{o}^{3+}-3d^6-$ all are paired (n = 0)

${\left[NiC{l}_4\right]}^{2-}\to N{i}^{2+}-3d^8\to \left(n=2\right)$

${\left[Cu{\left(N{H}_3\right)}_4\right]}^{2+}\to C{u}^{++}\to 3d^9\to \left(n=1\right)$

Indium and other semi conducting materials behaves different characteristic of impurities and pure particle at high temperature zone. Hence in metallurgical process it is refined by the zone refining.

Buna-S required nascent oxygen

Butadiene + styrene $\underset{}{\overset{\left[0\right]}{\to }}$ (Buna-S)

For 3S number of radial nodes are

= $n-\mathcal{l}-1=3-0-1=2$