Chemistry

The solubility of Ca(OH)₂ in water is:

[Given : The solubility product of Ca(OH)₂ in water = 5.5 * 10^-6]

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Chemistry Class 12th

Identify A and B in the chemical reaction

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Chemistry Class 12th

The correct sequence of reagents used in the preparation of 4-bromo-2-nitroethyl benzene from benzene is

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Chemistry Chemistry Chemical Bonding and Molecular Structure

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Conversion form

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Which among the following species has unequal bond lengths?

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SF₄ has sp³d hybridization and one type is axial while other type is equatorial

SiF₄ has sp³ (all bonds are equal)

$B F_{4}^{-}$ has sp³ (all bonds are equal)

XeF₄ has sp³d² and shape is sq. planar (All bonds are equal)

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Chemistry Class 12th

Which one of the following statements is FALSE for hydrophilic sols?

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Chemistry Chemistry Organic Chemistry

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Viscosity of the hydrophilic sol is always higher than H₂O, because dispersed phase particle attracted by dispersion medium.

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Consider the following chemical reaction.

$H C \equiv C H \to_{2) C O, H C l, A l C l_{3}}^{1) R e d h o t F e t u b e, 873 K} P r o d u c t$

The number of sp² hybridized carbon atoms (s) present in the product is--------------.

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Given below are two statements:

Statement I : α and β forms of sulphur can change reversibly between themselves with slow heating or slow cooling.

Statement II : At room temperature the stable crystalline form of sulphur is monoclinic sulphur.

In the light of the above statements, choose the correct answer from the options given below

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Using the provided information in the following paper chromatogram: Fig : Paper chromatography for compounds A and B. The calculated R_f value of A------------* 10^-1

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$R_{f} v a l u e = \frac{D i s t a n c e m o v e d b y s u b s t a n c e f r o m b a s e l i n e}{D i s t a n c e m o v e d b y t h e s o l v e n t f r o m b a s e l i n e} = \frac{2}{5} = 0.4 = 4.0 * 1 0^{- 1}$

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The ionization enthalpy of Na⁺ formation from Na_(g)is 495.8 kJ mol^-1, while the electron gain enthalpy of Br is - 325.0 kJ mol^-1. Given the lattice enthalpy of NaBr is - 728.4 kJ mol^-1. The energy for the formation of NaBr ionic solid is (-) -------------- * 10^-1kJ mol^-1.

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Δ H_{s u b} o f N a m e t a l = 496 k J / m o l e

Bond dissociation energy of Br₂ = 228 kJ/mole

$Δ H_{f} = 495.8 + - 325 - 728.4 = - 557.6 k J / m o l e = - 5576 * 1 0^{- 1} k J / m o l e$

Note : In question is neglect $Δ_{a} H^{0} o f N a, Δ_{v a p} H^{O} o f B r_{2} (l) a n d Δ_{b o n d} H^{0} o f B r_{2} (g)$

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