Chemistry

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Payal Gupta

Contributor-Level 10

I > III > IV > II

[FeF6]3−→Fe3+−3d5− all are unpaired (n = 5)

[Co (NH3)6]3+→Co3+−3d6− all are paired (n = 0)

[NiCl4]2−→Ni2+−3d8→ (n=2)

[Cu (NH3)4]2+→Cu++→3d9→ (n=1)

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Payal Gupta

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Indium and other semi conducting materials behaves different characteristic of impurities and pure particle at high temperature zone. Hence in metallurgical process it is refined by the zone refining.

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alok kumar singh

Contributor-Level 10

Buna-S required nascent oxygen

Butadiene + styrene → [ 0 ] (Buna-S)

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alok kumar singh

Contributor-Level 10

For 3S number of radial nodes are

= n − l − 1 = 3 − 0 − 1 = 2

          

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Payal Gupta

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Ca (OH)2 ?  Ca+ + 2OH-

S                      S           2S

∴ K s p = 4 S 3

            

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alok kumar singh

Contributor-Level 10

Kindly go through the solution

 

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Payal Gupta

Contributor-Level 10

Conversion form

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Payal Gupta

Contributor-Level 10

SF4 has sp3d hybridization and one type is axial while other type is equatorial

SiF4 has sp3 (all bonds are equal)

B F 4 − has sp3 (all bonds are equal)

XeF4 has sp3d2 and shape is sq. planar (All bonds are equal)

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Payal Gupta

Contributor-Level 10

Viscosity of the hydrophilic sol is always higher than H2O, because dispersed phase particle attracted by dispersion medium.

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a year ago

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alok kumar singh

Contributor-Level 10

Kindly go through the solution

 

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