Chemistry

CS₂ is non-polar, non-ionisable solvent and produce only para substituted compound due to the production of less Br⁺ ion, while H₂O itself a polar solvent and produce sufficient concentration of Br⁺ to attack on ortho and para position.

Bakelite formed by the condensation reaction of phenol with formaldehyde and it is a thermosetting polymer/ plastics.

Electronic configuration of $O_2^{-}$ anion is;

${\left(\sigma 1s\right)}^2{\left({\sigma }_{1s}^{*}\right)}^2{\left({\sigma }_{2s}\right)}^2{\left({\sigma }_{2s}^{*}\right)}^2{\left(\sigma 2pz\right)}^2{\left(\pi 2px\right)}^2={\left(\pi 2py\right)}^2{\left(\pi *2px\right)}^2={\left(\pi *2py\right)}^1$

In anion total 10 e^- resides in Bonding Molecular Orbitals and 7e^- resides in anti-Bonding Molecular orbitals. Hence bond order $=\frac{10-7}{2}=\frac{3}{2}=1.5.$

It is paramagnetic due to one unpaired electron.

Heavy water (D₂O) is used to study reaction mechanism. O-H bond energy is less than O-D, hence it will produce fast reaction than O-D. Here assertion is true but Reason is false.

$\left[Co{\left(N{H}_3\right)}_3{\left(N{O}_2\right)}_3\right]$ shows Facial and Meridional geometrical isomerism.

$\left[CoC{l}_2{\left(en\right)}_2\right]$ shows cis and trans geometrical isomerism.

${\left[Co{\left(N{H}_3\right)}_{4}C{l}_2\right]}^{+}$  shows cis and trans geometrical isomerism.

${\left[Co{\left(CN\right)}_5\left(NC\right)\right]}^{3-}$ can not show geometrical isomerism.

When AgNO₃ added to Kl solution, it form precipitate of Agl (s) which absorb I^- ions from Kl and colloidal particles become negatively charged.

All hydrogens are attached to oxygen are ionisable.

Following are the possible isomers of 1, 2-dimethyl cyclopropane