Chemistry

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New answer posted

a year ago

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V
Vishal Baghel

Contributor-Level 10

In stratosphere CFC get broker down by powerful UV/radiation releasing Cl·

C F 2 C l 2 ( g ) → U V C l • ( g ) + C • F 2 C l ( g )

New answer posted

a year ago

0 Follower 19 Views

V
Vishal Baghel

Contributor-Level 10

This is isomeric form of Uracil, which is present in RNA

New answer posted

a year ago

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V
Vishal Baghel

Contributor-Level 10

=> Assertion is correct but Reason is not correct

New answer posted

a year ago

0 Follower 12 Views

V
Vishal Baghel

Contributor-Level 10

CrO3 : mild oxidizing agent

New answer posted

a year ago

0 Follower 4 Views

V
Vishal Baghel

Contributor-Level 10

Kindly consider the following figure

New answer posted

a year ago

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R
Raj Pandey

Contributor-Level 9

Acid = M (OH)2 Salt + H2O

M.E of Acid = me of Base

∴ 1 0 * ( 0 . 1 * n f ) = ( 0 . 0 5 * 2 ) * 3 0

∴ n f = 3

Thus basicity of acid = 3

New answer posted

a year ago

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R
Raj Pandey

Contributor-Level 9

Biuret test is given by proteins and dipeptide & compounds having following groups

Hence positive test given by tripeptide & biuret.

New answer posted

a year ago

0 Follower 5 Views

R
Raj Pandey

Contributor-Level 9

Monomer of novolac is

Molecular mass of monomer unit

              = 12 * 7 + 1 * 8 + 16 * 2

              = 84 + 8 + 32

              = 124 g

Molecular mass of polymer = 963 g

∴ n * mass of monomer = mass of polymer + (n – 1) * 18

(n – 1) unit of H2O is removed during formation

∴ 1 2 4 * n = 9 6 3 + 1 8 ( n − 1 )

106n = 945

  ∴ n = 9 4 5 1 0 6 = 8 . 9 1 ≈ 9

New answer posted

a year ago

0 Follower 10 Views

R
Raj Pandey

Contributor-Level 9

FeCl3. 3H2O i.e. [Fe (H2O)3], K3 [Fe (CN]6 and [Co (NH3)6]Cl3 the last two complex are inner-orbital complex due to presence of strong ligand.

∴ Δ 0     o f     K 3 [ F e ( C N ) 6 ] > Δ 0 o f     [ C o ( N H 3 ) 6 ] C l 3

Because CN- is strong ligand

∴ Δ 0 ∝ 1 λ

More Δ 0 smaller value of absorbed λ

K 3 [ F e ( C N ) 6 ] → F e + 3 = 4 s 0 3 d 5 4 p 0

∴ u . e = 1

∴ μ = 1 * ( 1 + 2 ) B . M = 3 B . M

= 1.732 B.M

≈ 2

New answer posted

a year ago

0 Follower 3 Views

R
Raj Pandey

Contributor-Level 9

Number of replaceable H is 2.

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