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5 months ago

Chemistry Class 12th

The Major Product in the above reaction is :

 
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A
alok kumar singh

Contributor-Level 10

Kindly go through the solution

 

New answer posted

5 months ago

Chemistry Class 11th

A cylindrical container of volume 4.0 * 10-3 m3 contains one mole of hydrogen and two moles of carbon dioxide. Assume the temperature of the mixture is 400K. The pressure of the mixture of gases is : [Take gas constant as 8.3J mol-1 K-1]
0 Follower 2 Views

A
alok kumar singh

Contributor-Level 10

P = n R T V = ( 1 + 2 ) * 8 . 3 * 4 0 0 4 . 0 * 1 0 ? 3 = 2 4 . 9 * 1 0 5 P a

New answer posted

5 months ago

Chemistry Class 12th

In the above reaction product B is:

AqIn the above reaction product B is

 
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A
alok kumar singh

Contributor-Level 10

Kindly go throiugh the solution

 

New answer posted

5 months ago

Chemistry Class 12th

Match List I with List II

List I

Pollutant

List II

Disease / sickness

A.

Benzenesulphonyl chloride

I.

Test for primary aminies

B.

Hoffmann bromamide reaction

II.

Anti saytzeff

C.

Carbylamine reaction

III.

Hinsberg reagent

D.

Hoffman orientation

IV.

Known reaction of isocyanates

Choose the correct answer from the options given below ;
0 Follower 3 Views

A
alok kumar singh

Contributor-Level 10

Intermediate : R – N = C = O (Isocyanate)

(C) Carbylamine reaction ->Test for primary amine.

  R − N H 2     o r     A r − N H 2 + C H C l 3 + 3 K O H → R − N C     o r     A r − N C + 3 K C l + 3 H 2 O                    

(D) Hoffmann orientation -> Anti saytzeff (Formation of less substituted alkene as major product)

 

New answer posted

5 months ago

Chemistry Class 12th

In carius method of estimation of halogen, 0.45g of an organic compound gave 0.36g of AgBr. Find out the percentage of bromine in the compound.

 (Molar masses: AgBr = 188 g mol-1, Br = 80 g mol-)
0 Follower 3 Views

A
alok kumar singh

Contributor-Level 10

Mass of organic compound = 0.45 gm

Mass of AgBr obtained = 0.36 gm

∴ M o l e s     o f     A g B r = 0 . 3 6 1 8 8

∴ M a s s     o f     B r o m i n e = 0 . 3 6 1 8 8 * 8 0 = 0 . 1 5 3 2 g m

∴ % B r     i n     c o m p o u n d = 0 . 1 5 3 2 0 . 4 5 * 1 0 0 = 3 4 . 0 4 %                

 

New answer posted

5 months ago

Chemistry Class 12th

Match List I with List II

Choose the correct answer from the options given below:

 
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A
alok kumar singh

Contributor-Level 10

Kindly go through the solution
 

 

 

New answer posted

5 months ago

Chemistry Class 12th

Which one of the following is an example of artificial sweetner?
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V
Vishal Baghel

Contributor-Level 10

Alitame is an artificial sweetener. It is a second generation of dipeptide sweetener. It is 200 times sweeter than sucrose.

New answer posted

5 months ago

Chemistry Class 12th

Using very little soap while washing clothes, does not serve the purpose of cleaning of clothes, because:
0 Follower 1 View

V
Vishal Baghel

Contributor-Level 10

Micelles are not formed because it formed above CMC.

New answer posted

5 months ago

Chemistry Class 12th

The reaction  with bromine and KOH gives RNH2 as the end product. Which one the

following is the intermediate product formed in this reaction?
0 Follower 2 Views

V
Vishal Baghel

Contributor-Level 10

Kindly consider the following figure

New answer posted

5 months ago

Chemistry Biomolecules

A sugar 'X' dehydrates very slowly under acidic condition to give furfural which on further reaction with resorcinol given the coloured product after sometime.

Sugar 'X' is
0 Follower 5 Views

A
alok kumar singh

Contributor-Level 10

Kindly go through the solution

 

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