Chemistry

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New answer posted

a year ago

0 Follower 6 Views

V
Vishal Baghel

Contributor-Level 10

 t1/2α [Reactant]t=0 (1−n),  where n = order of reaction.

New answer posted

a year ago

0 Follower 6 Views

V
Vishal Baghel

Contributor-Level 10

Fe3O4 + 8H+ + 8e -> 3Fe + 4H2O

New answer posted

a year ago

0 Follower 8 Views

V
Vishal Baghel

Contributor-Level 10

K e q = ( 1 2 * 1 0 1 5 ) 1 / 2 = 2 . 2 4 * 1 0 ? 8

New answer posted

a year ago

0 Follower 9 Views

V
Vishal Baghel

Contributor-Level 10

Remaining volume of solution = 400 ml

Mass of HNO3 = 25.2 – 11.5 = 13.7

Molarity =  (13.7/63) (400/1000) = 0.54 M = 54 * 10-2 M

New answer posted

a year ago

0 Follower 10 Views

V
Vishal Baghel

Contributor-Level 10

 C (s)+O2 (g)→CO2 (g)Δng=0

qC=20*2=40kJ

Number of moles of C = 2.412=0.2  moles

ΔHC=40kJ0.2mole=200kJ/mole

New answer posted

a year ago

0 Follower 5 Views

V
Vishal Baghel

Contributor-Level 10

Xe = Xn

MeVe = MnVn

VeVn=MnMe∼1758.24

New answer posted

a year ago

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V
Vishal Baghel

Contributor-Level 10

 xH2=nH2nH2+no2= (40/2) (40/2)+ (60/32) = 0.914

PH2=xH2*PT=0.914*2.2∼2bar

New answer posted

a year ago

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V
Vishal Baghel

Contributor-Level 10

Mass of solute = 48 * 2 * 10-3 gram

Atoms of Mg = 24.08 * 1020

New answer posted

a year ago

0 Follower 21 Views

V
Vishal Baghel

Contributor-Level 10

Aniline makes adduct with AlCl3 and thus gets deactivated for electrophilic aromatic substitution and do not react with CH3-Cl

New answer posted

a year ago

0 Follower 16 Views

V
Vishal Baghel

Contributor-Level 10

Reducing sugar must have hemi-acetal group and option (A) has that group.

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