Chemistry
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New answer posted
a year agoContributor-Level 10
Remaining volume of solution = 400 ml
Mass of HNO3 = 25.2 – 11.5 = 13.7
Molarity = = 0.54 M = 54 * 10-2 M
New answer posted
a year agoNew answer posted
a year agoContributor-Level 10
Aniline makes adduct with AlCl3 and thus gets deactivated for electrophilic aromatic substitution and do not react with CH3-Cl
New answer posted
a year agoContributor-Level 10
Reducing sugar must have hemi-acetal group and option (A) has that group.
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