Chemistry

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New answer posted

a year ago

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A
alok kumar singh

Contributor-Level 10

In reducing action, H2O2 changes to O2 because it will oxides but option (A) is in acidic medium, hence answer will be (C).

New answer posted

a year ago

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A
alok kumar singh

Contributor-Level 10

KCN is used as depressant for ZnS. While Au and Ag, cyanide process (leaching) is used.

New answer posted

a year ago

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A
alok kumar singh

Contributor-Level 10

Correct electronic configuration of Pt is 78Pt = [Xe]4f145d96s1

It is an exceptional electronic configuration

New answer posted

a year ago

0 Follower 2 Views

A
alok kumar singh

Contributor-Level 10

Due to equal and similar charge particle will repel each other, hence will never precipitate

New answer posted

a year ago

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A
alok kumar singh

Contributor-Level 10

Due to common ion effect solubility of AgCl will decreases in KCl, AgCl and AgNO3 but in deionized water, no common ion effect will takes place so maximum solubility.

New answer posted

a year ago

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alok kumar singh

Contributor-Level 10

Covalent character is LiCl>NaCl>KCl>CsCl. As the cationic size increases polarization decreases.

∴ Covalent character decreases.

New answer posted

a year ago

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A
alok kumar singh

Contributor-Level 10

(A) Cr = [Ar]3d54s1

(B) m = −l  to+l

(C) According to Aufbau principle, orbital are filled in order of their increasing energies.

(D) Total nodes = n – 1

New answer posted

a year ago

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A
alok kumar singh

Contributor-Level 10

Moles of Fe3O4 = 4.64*103232=20

Moles of CO = 2.52*10328=90

So limiting reagent = Fe3O4

So moles of Fe formed = 60

Weight of Fe = 60 * 56 = 3360

 

New answer posted

a year ago

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P
Payal Gupta

Contributor-Level 10

(a) Sucrose  → α-D glucose and β-D fructose

(b) Lactose  → β-D- galactose and β-D glucose

(c) maltose  → α-D glucose and α-D-glucose

New answer posted

a year ago

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P
Payal Gupta

Contributor-Level 10

Consider the following image

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