Chemistry
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New answer posted
a year agoContributor-Level 10
Where, K2 is at 310 K and K1 at 300K
K2 = K1 * 103
K1 = K2 * 10-3
x = 1
New answer posted
a year agoContributor-Level 10
At anode (oxidation)
2H2O O2 (g) + 4H+ + 4e-
At cathode (Reduction)
2H+ + 2e- H2 (g)
No. of gm- equivalents =
New answer posted
a year agoContributor-Level 10
Mass = d * v = 1.02 * 1.2 = 1.224gm
Moles of acetic acid = 0.0204 moles in 2L
So molality = 0.0102 mol/kg
i = 1 + a for acetic acid
0.0198 = (1 + a) * 1.85 * 0.0102
α = 0.04928 = 5%
New answer posted
a year agoContributor-Level 10
85gm NH3 = 5 moles of NH3
Enthalpy change for 1 mol = 23.4 kJ
Then enthalpy change for 5 mol = 23.4 * 5 = 117 kJ
New answer posted
a year agoNew question posted
a year agoTaking an Exam? Selecting a College?
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