Chemistry

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New answer posted

8 months ago

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V
Vishal Baghel

Contributor-Level 10

85gm NH3 = 5 moles of NH3

Enthalpy change for 1 mol = 23.4 kJ

Then enthalpy change for 5 mol = 23.4 * 5 = 117 kJ

New answer posted

8 months ago

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V
Vishal Baghel

Contributor-Level 10

Assuming ideal behaviour,  P=dRTM

P=100760atm, T=257+273=530K

d = 0.46gm/L

M=0.46*0.082*530100*760=151.93152g/mol

New answer posted

8 months ago

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A
alok kumar singh

Contributor-Level 10

Kindly go through the solution

 

New answer posted

8 months ago

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V
Vishal Baghel

Contributor-Level 10

Kindly consider the following figure

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8 months ago

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V
Vishal Baghel

Contributor-Level 10

  [Co (H2O)6]Cl2Co2+3d7t2g5eg2

Number of unpaired electrons = 3

[Cr (H2O)6]Cl3Cr3+3d3t2g3eg0

Number of unpaired electrons = 3

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New answer posted

8 months ago

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V
Vishal Baghel

Contributor-Level 10

 t1/2α [Reactant]t=0 (1n),  where n = order of reaction.

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Vishal Baghel

Contributor-Level 10

Fe3O4 + 8H+ + 8e -> 3Fe + 4H2O

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Vishal Baghel

Contributor-Level 10

K e q = ( 1 2 * 1 0 1 5 ) 1 / 2 = 2 . 2 4 * 1 0 ? 8

New answer posted

8 months ago

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V
Vishal Baghel

Contributor-Level 10

Remaining volume of solution = 400 ml

Mass of HNO3 = 25.2 – 11.5 = 13.7

Molarity =  (13.7/63) (400/1000) = 0.54 M = 54 * 10-2 M

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