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a year ago

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P
Payal Gupta

Contributor-Level 10

This is a short answer type question as classified in NCERT Exemplar

Ice has a highly ordered 3D hydrogen bonded structure. Each oxygen atom is surrounded tetrahedrally by four other oxygen atoms at a distance of 276 pm.

New answer posted

a year ago

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V
Vishal Baghel

Contributor-Level 10

This is a Short Answer Type Questions as classified in NCERT Exemplar

Ans: As, NH3 is Lewis base while BF3  is Lewis acid. Lewis electronic theory of acids and bases explains it. Hybridisation state: N in NH3 is sp3 hybridised and Boron in BF3 is sp2 hybridised.

New answer posted

a year ago

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Vishal Baghel

Contributor-Level 10

This is a Short Answer Type Questions as classified in NCERT Exemplar

Ans:

Ksp=3.2 * 10-8

PbCl2? Pb2+ +2Cl-

Ksp= (S) (2S)2

Ksp=4S3

s3=43.2 * 10-8

s3=8 * 10-9

s=2 * 10-3

Molar   mass   of   PbCl2=278g/mol   

By using Molarity formula,      

2 * 10-3= 278 *  x0.1

x= 0.1 278   *   2   *   10 - 3

 

= 100 278   *   2  

x=0.18L   

New answer posted

a year ago

0 Follower 2 Views

V
Vishal Baghel

Contributor-Level 10

This is a Short Answer Type Questions as classified in NCERT Exemplar

Ans: Let us assume S be the solubility of Al (OH)3.

Ksp= [Al3+] [OH-]3= (S) (3S)3=27S4

S4=27Ksp=27 * 1027 * 10-11=1 * 10-12

S=1*10−3 mol L-1.

(i) Solubility of Al (OH)3 ? : Molar mass of Al (OH)3  is 78g. Hence, solubility of Al (OH)3 ? in gL-1=1 * 103 * 78gL-1=78 * 10-3gL1=7.8 * 10-2gL-1
(ii) pH of the solution: S=1* 10−3mol L-1

OH=3S= 3*1* 10−3 = 3* 10−3

pOH=3−log3

pH=14−pOH= 11+log3= 11.4771.

New answer posted

a year ago

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V
Vishal Baghel

Contributor-Level 10

This is a Short Answer Type Questions as classified in NCERT Exemplar

Ans: we can find the pH of the solution as-

pH of solution A=6

Hence, concentration of  [H+] ion in solution A=10-6mol L-1

pH of solution B=4

Therefore, concentration of  [H]+ ion in solution B=10-4mol L-1

On mixing one litre of each solution, total volume = 1L+1L=2L.

Amount of H+ ions in 1L of solution

 A= concentration* Volume (V)= 10-6mol* IL 

Amount of H+ ions in 1L of solution B=10-4mol*1L

∴ Total amount of H+ ions in the solution formed by mixing

...more

New answer posted

a year ago

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P
Payal Gupta

Contributor-Level 10

This is a short answer type question as classified in NCERT Exemplar

NaH belongs to Saline hydrides and B2H6 and H2O belong to molecular hydrides.

New answer posted

a year ago

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Vishal Baghel

Contributor-Level 10

This is a Short Answer Type Questions as classified in NCERT Exemplar

Ans: pH of HOCL = 2.85

But, - pH = log [H+]

 -2.85=log [H+]

= -3.15 = log [H+]

  [H+]=anti log3.15

  [H+]= 1.413* 10-3 

or weak mono basic acid

[H+]= K a *  C

= K a  = H + 2 C  = 1.43 * 10 - 3 2     0.08

=24.957 * 10-6

=2.4957 * 10-5

New answer posted

a year ago

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V
Vishal Baghel

Contributor-Level 10

This is a Short Answer Type Questions as classified in NCERT Exemplar

Ans: The chemical equation is given below-  

                                                           BaSO4(s) → Ba2+(aq) + SO42-(aq)

At t = 0                        &

...more

New answer posted

a year ago

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V
Vishal Baghel

Contributor-Level 10

This is a Short Answer Type Questions as classified in NCERT Exemplar

Ans: Given with the pH = 5 as, pH= - log  [ H+ ] 

  [ H+ ] =10-5M

On 100 times dilution-

  [ H+ ] =10-7M.

New answer posted

a year ago

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P
Payal Gupta

Contributor-Level 10

This is a short answer type question as classified in NCERT Exemplar

These are formed by many d-block and/block elements. However, the metals of group 7, 8 and 9 do not form hydride. Unlike saline hydrides, they are almost always non- stoichiometric, being deficient in hydrogen. For example, LaH 2.87, YbH 2.55, TiH 1.5-1.8, ZrH 1.3-1.75. Dihydrogen forms molecular compounds with most of the jp-block elements.

Most familiar examples are CH4, NH3, H2O and HF.

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