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New answer posted
10 months agoContributor-Level 10
24. As an effect of lanthanide contraction, the second and third rows of transition elements resemble each other. For example, zirconium and hafnium have similar radius i.e. 160pm and 159pm respectively. Due to this similarity in their size, they show similar physical and chemical properties.
Lanthanoid contraction: Because the elements in Row 3 have 4f electrons. These electrons do not shield good, causing a greater nuclear charge. This greater nuclear charge has a greater pull on the electrons and result in the decrease in their size and atomic radii.
New answer posted
10 months agoContributor-Level 10
43. Option (i) and (ii)
In the vapor phase refining method, the metal is converted into its volatile compound and then is collected elsewhere. This involves two techniques:
1. Mond Process for refining Nickel: in this process, a volatile complex, nickel tetracarbonyl is formed when nickel is heated with a stream of carbon monoxide.
2. Van Arkel Method for refining Zirconium or Titanium: this method is basically used for removal of oxygen and nitrogen present as impurities in the Zr or Ti metal. These are heated in an evacuated metal with iodine. As iodine is more covalent than these metals, it volatilizes.
New answer posted
10 months agoContributor-Level 10
23. KMnO4 act as an oxidising agent however it's activity as oxidising agent is influenced by the pH of the solution i.e. acidic, basic or neutral solution.
K2Cr2O7 + 2KOH → 2K2CrO4 + H2O
(Orange) (yellow)
2K2CrO4 + H2SO4 → K2Cr2O7 + K2SO4 + H2O
(yellow) (orange)
New answer posted
10 months agoContributor-Level 10
22. This is due to the inter conversion of dichromate (orange) to chromate ion (yellow).
Cr2O72- CrO42-
(orange) (yellow)
New answer posted
10 months agoContributor-Level 10
42. Option (i) and (iv)
(i) Carbon monoxide is the primary reducing agent in the furnace.
(ii) This is an endothermic reaction in which heat is absorbed from the furnace. As a result, it is critical not to add too much limestone, as this will cool the furnace. Calcium oxide is a basic oxide that reacts with acidic oxides in the rock, such as silicon dioxide. Calcium silicate is formed when calcium oxide reacts with silicon dioxide.
New answer posted
10 months agoContributor-Level 10
21. 2MnO4- + 16H+ + 5C2O42- → 2Mn2 + + 8H2O + 10CO2
KMnO4 oxidises the oxalic acid to CO2 and reduces itself to Mn2+ state. Mn2+ is colourless that's why it seems that KMnO4 has been disappeared.
New answer posted
10 months agoContributor-Level 10
41. Option (i) and (iii)
Explanation: Haematite is an ore of iron that can be calcined and reduced by carbon. In the metallurgical process, calamine ore is calcined ore that can be reduced by carbon. Hence, option (i) and (ii) are correct.
New answer posted
10 months agoContributor-Level 10
20. Ce = 4f1 5d1 6s2
Ce3 + = 4f1 5d0 6s0
As in Ce3+ ,
4f has only single electron. Cerium holds the capacity to lose this electron also and attain 4f0 configuration which is more stable.
Ce4+ = 4f0 5d0 6s0
Hence it shows 4+ oxidation states.
New answer posted
10 months agoContributor-Level 10
19. As an effect of lanthanoid contraction, zirconium and hafnium have similar radius of 160 pm and 159 pm respectively. Due to this similarity in their size, they show similar physical and chemical properties.
Lanthanoid contraction: Because the elements in Row 3 have 4f electrons. These electrons do not shield good, causing a greater nuclear charge. This greater nuclear charge has a greater pull on the electrons and result in the decrease in their size and atomic radii.
New answer posted
10 months agoContributor-Level 10
40. Option (i) and (iii)
Calcination is the process of heating when the volatile matter escapes, leaving the metal oxide behind. It is usually done in the absence of air.
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