Chemistry

HBrO2 has least existence

Kindly consider the following figure

Kindly go therough the solution

NO is a neutral oxide. 

Hydroboration oxidation : The reaction proceeds in an anti Markovnikov manner

=> No rearrangement is possible

Orbital angular momentum = $\frac{nh}{2\pi }$ $\frac{}{}$

= $\frac{3h}{2\pi }\left(?n=3\right)$

CaC₂ + 2H₂O Ca (OH)2 + C2H2

Number of molecules   $=\frac{w\left(g\right)}{M\left(g\right)}*N_A$

=  $\frac{56}{28}*N_A$

= 2 N_A

Fe₃O₄ is a ferromagnetic substance

Malachite : CuCO3.Cu (OH)2

Azurite : 2CuCO3.Cu (OH)2

Cuprite : Cu₂O

Copper pyrite : Cu₂S.Fe₂S₃.

For BCC unit cell

$\sqrt[]{3}a=4r$

$a=\frac{4r}{\sqrt[]{3}}$