Chemistry

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Haemoglobin is a positive colloid. Hence greater is the charge of anion, more effective will be the coagulation of haemoglobin.

$$ Correct order of coagulating power is $P{O}_4^{3-}>S{O}_4^{2-}>C{l}^{-}$

BF₃ : sp2 hybridised hence shape will be trigonal planar.

Electrophoresis : The migration of colloidal particles under the influence of an electric field is known as electrophoresis.

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$r_1=k{\left[x\right]}^n$ … (i)

$$ $2r_1=k{\left[4x\right]}^n$  … (ii)

$\left(ii\right)÷\left(i\right)$

$\Rightarrow \frac{2r_1}{r_1}=\frac{k{\left[4x\right]}^n}{k{\left[x\right]}^n}$

$\Rightarrow 2={\left(2\right)}^{2n}$

$\Rightarrow n=\frac{1}{2}$

XeF2 : Hybrid orbital = sigma bond + L.P

= 2 + 3

= 5 = sp3d

Shape will be linear

For a first order reaction.

$k=\frac{0.693}{t_{\raisebox{1ex}{$1$}\!\left/ \!\raisebox{-1ex}{$2$}\right.}}=\frac{0.693}{231}=3*10^{-3}{s}^{-1}$   

Z=109 : Unnilennium = Meitnerium