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11 months ago

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A
alok kumar singh

Contributor-Level 10

11.53 

1. When N –propyl methyl ether reacts with HBr, it forms propanol and bromomethane, n- propyl methyl ether will cleave at O . and H+ will attack at O, and Br- will attack CH +

2. When Ethoxybenzene Reacts with HBr, it forms Phenol and bromoethane, Ethoxybenzene cleaves at H+ will attack at O, and Br- will attack C H +

3. When nitrating mixture reacts with ethoxy benzene introduction of nitro group is occurred at para position as it will give the stable product without

4. As HI is a strong nucleophile it will protonate the oxygen, to form a good leaving And I- will attack at C (CH3)3+ to give tert- butyl iodide and ethanol.

New answer posted

11 months ago

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Payal Gupta

Contributor-Level 10

4.34. The combining atomic orbitals should have comparable energies like, 1s orbital of one atom can combine with 1s atomic orbital of another atom, 2s can combine with 2s.

The combining atomic orbitals must have proper orientations so that they are able to overlap to a considerable extent.

The extent of overlapping should be large.

New answer posted

11 months ago

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alok kumar singh

Contributor-Level 10

11.52

Set (ii) is appropriate Because CH3Br is only a nucleophile whereas CH3ONa is nucleophile as well as strong base, so the elimination reaction can occur,

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11 months ago

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Payal Gupta

Contributor-Level 10

4.33. Let us consider the combination between atoms of hydrogen HA and HB and eA and eB be their respective electrons.

As they tend to come closer, two different forces operate between the nucleus and the electron of the other and vice versa. The nuclei of the atoms as well as their electrons repel each other. Energy is needed to overcome the force of repulsion. Although the number of new attractive and repulsive forces is the same, but the magnitude of the attractive forces is more. Thus, when two hydrogen atoms approach each other, the overall potential energy of the system decreases. Thus, a stable molecule of hydrogen is formed

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New answer posted

11 months ago

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A
alok kumar singh

Contributor-Level 10

11.51

During Williamson synthesis of ethers, an alkyl halide reacts with an alkoxide (ion with –ve charge on the oxygen of alcohol and + ve charge on alkali metal like Na) ion. it is an SN2 reaction. In the reaction, alkyl halides should be least hindered. Hence, an alkyl halide is obtained from ethanol and alkoxide ion from 3-methylpentan-2-ol. The reactions are shown below:

New answer posted

11 months ago

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A
alok kumar singh

Contributor-Level 10

11.50 

1. Phenol on mixing with chloroform and NaOH at 340K followed by Acidic hydrolysis, salicyl aldehyde is formed. When carbon tetrachloride (CCl4) is used at the place of chloroform salicylic acid is This type of reaction is known as Reimer - Tiemann reaction.

2. The sodium phenoxide reacts with CO2 under pressure 4-7 atm at a 400K temperature to form sodium salicylate, which on acidification yields salicylic acid. This type of reaction is known as Kolbe's

New answer posted

11 months ago

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alok kumar singh

Contributor-Level 10

11.49.

Resonating structures of o-nitrophenoxide ions that are formed by the loss of a proton from o-nitrophenol are as follows:

Resonating structures of p-nitrophenoxide ions that are formed by the loss of a proton from p- nitrophenol are as follows:

Resonating structures of phenoxide ions that are formed by the loss of a proton from phenol are as follows:

It is clearly evident from the above structures that due to —R-effect of— NO2NO2 group, o-and p-nitrophenoxide ions are more stable than phenoxide ions. Consequently, o- and p- nitrophenols are more acidic than phenols.

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11 months ago

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New question posted

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New answer posted

11 months ago

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A
alok kumar singh

Contributor-Level 10

11.47

(a) (i) Primary alcohols do no react appreciably with Lucas' reagent (HCl –ZnCl2) at room temperature.

      (ii) Tertiary alcohol reacts immediately with Lucas 'reagent.

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