Chemistry

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New answer posted

a year ago

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V
Vishal Baghel

Contributor-Level 10

(b) It is a nucleophilic substitution reaction. KOH (aq) provides OH- ion for the nucleophile attack.

New answer posted

a year ago

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A
alok kumar singh

Contributor-Level 10

11.27

ortho-nitro phenol is more acidic than ortho-methoxy phenol.

Explanation: Due to strong –R and –I effect of NO2 group, electron density in the O-H bond decreases and hence the loss of a proton becomes easy.

Now after the loss of a proton, the o-nitrophenoxide ion left behind is stabilized by resonance and thus making o-nitro phenol a stronger acid.

In contrast, due to the +R effect of methoxy group increases the electron density in the O-H bond. Thereby making the loss of proton difficult.

Now, the o-methoxyphenoxide ion left after the loss of a proton is destabilized by resonance. The two negative charges repel each other, thereb

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New answer posted

a year ago

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V
Vishal Baghel

Contributor-Level 10

(d) Is the correct answer.

New answer posted

a year ago

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V
Vishal Baghel

Contributor-Level 10

(b) Is the most stable since it is a tertiary carbocation.

New answer posted

a year ago

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V
Vishal Baghel

Contributor-Level 10

(b) Iron (III) hexacyanidoferrate (II) (or ferriferrocyanide) Fe4 [Fe (CN)6]3  is the correct answer.

New answer posted

a year ago

0 Follower 79 Views

A
alok kumar singh

Contributor-Level 10

11.26 

The acidic nature of phenol can be represented by the following two reactions:-

(a) Phenols react with sodium to give sodium phenoxide, liberating H2.

(b) Phenols react with sodium hydroxide to give sodium phenoxide and water as a by-product.

The acidity of phenol is more than that of ethanol. This is because phenol after losing a proton becomes phenoxide ion which undergoes resonance and is stabilized whereas ethoxide ion does not.

The resonating structures of phenoxide ion are shown as below:

The lone pair of electrons on oxygen delocalizes into the benzene (mesomeric effect) which reduces the electron density in the O-H bon

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New question posted

a year ago

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New answer posted

a year ago

0 Follower 10 Views

V
Vishal Baghel

Contributor-Level 10

Mass of the compound = 0.468 g
Mass of barium sulphate= 0.668 g

% of sulphur = 

                     

New answer posted

a year ago

0 Follower 8 Views

V
Vishal Baghel

Contributor-Level 10

Mass of the compound = 0.3780 g
Mass of silver chloride = 0.5740 g

% of chlorine =

New answer posted

a year ago

0 Follower 34 Views

V
Vishal Baghel

Contributor-Level 10

Step I: Calculation of volume of unused acid i.e. V2 =?

V1 = Volume of NAOH solution required = 60 cm3 

N1 = Normality of NaOH solution = ½ N

N2 = Normality of H2SO4 = 1N

Applying N1V1 = N2V2

½ N x 60 cm3 = 1N x V2

Or V2 = 30 cm3

Step II: calculation of volume of acid used

Volume of acid added = 50 cm3

Volume of unused acid = 30 cm3

Volume of acid used = 50 – 30 = 20 cm3

Step III: Calculation of % of nitrogen

Mass of compound = 0.50 g

Volume of acid used = 20 cm3

Normality of acid used = 1 N

% of nitrogen = (1.4 x 20 x 1) / 0.50 = 56%

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