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New answer posted
a year agoContributor-Level 10
11.25
1-phenylethanol from a suitable alkene
The addition of water takes place according to Markovnikov rule. The alkene taken is styrene. And According to the rule, the positive charge i.e. H+ goes to the carbon of the double bond which has more number of hydrogens and the negative part i.e. OH- goes to the carbon that has less number of hydrogens. Therefore resulting the final product as 1-phenyl ethanol.
2. In the above conversion, NaOH gets dissociated into Na+ and OH-and Na+ then combines with Cl of chloromethylcyclohexane forming NaCl and thus the final product Cyclohexylmethanol is obtained.
3. In this conversion also,
New answer posted
a year agoContributor-Level 10
Step 1: Calculation of mass of CO2 produced
Mass of compound = 0.20 g
% of carbon = 69%
i.e. 12/44 x = Mass of Carbondioxide formed / Mass of Compound = 69/100
Therefore, mass of CO2formed = (69 x 44 x 0.20) / (12 x 100) = 0.506 g
Step 2: Calculation of mass of H2O produced
Mass of compound = 0.20 g
% of hydrogen = 4.8%
i.e. 2/18 x Mass of Water Formed/Mass of Compound = 4.8/100
Therefore, mass of H2O formed = 4.8*18*0.20/2*100 = 0.0864 g
New answer posted
a year agoContributor-Level 10
11.24
The reaction given below is:
Benzene reacts with concern. H2SO4 and undergoes the following mechanism:-
Step 1: The equilibrium produces SO3 in concentrated H2SO4, as shown below:
Step 2: SO3 is the electrophile which reacts with benzene to form arenium ion, as shown below:
Step 3: A proton is removed from the arenium ion to form benzenesulfonate ion.
Step 4: The benzenesulfonate ion accepts a proton to become benzene-sulphonic acid, as shown below:
Step 5: The benzene sulphonic acid then reacts with NaOH to give phenol as the final product, as shown below:
New answer posted
a year agoContributor-Level 10
It necessary to use acetic acid and not sulphuric acid for acidification of sodium extract for testing sulphur by lead acetate test because sulphuric acid will react with lead acetate to form a white precipitate of lead sulphate which will interfere in the test of sulphur.
Pb (OCOCH3)2 + H2SO4 →PbSO4 + 2CH3COOH
New answer posted
a year agoContributor-Level 10
CO2 is acidic in nature and therefore, it reacts with the strong base KOH to form K2CO3.
2KOH + CO2 ? K2CO3+ H2O.
New answer posted
a year agoContributor-Level 10
No. CCl4 is a completely non-polar covalent compound whereas AgNO3 is ionic in nature. Therefore, they are not expected to react and thus a white precipitate of silver chloride will not be formed.
New answer posted
a year agoContributor-Level 10
It is because in steam distillation the sum of vapour pressure of organic compound and steam should be equal to atmospheric pressure.
New answer posted
a year agoContributor-Level 10
Sublimation can be used for the separation of the two compounds because camphor can sublime whereas CaSO4 does not.
New answer posted
a year agoContributor-Level 10
Organic compound is fused with sodium metal so as to convert organic compounds into NaCN, Na2S, NaX and Na3PO4. Since these are ionic compounds and become more reactive and thus can be easily tested by suitable reagents.
New answer posted
a year agoContributor-Level 10
11.23
Step 1:- Protonation of ethene to form carbocation by electrophilic attack of H3O+.
Step 2:- Nucleophilic attack of water on carbocation.
Step 3:- Deprotonation to form ethanol.
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