Chemistry

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New answer posted

a year ago

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V
Vishal Baghel

Contributor-Level 10

(a) Crystallisation: In this process the impure solid is dissolved in the minimum volume of a suitable solvent. The soluble impurities pass into the solution while the insoluble ones left behind. The hot solution is then filtered and allowed to cool undisturbed till crystallisation is complete. The crystals are then separated from the mother liquor by filtration and dried.
Example: crystallisation of sugar.

(b) Distillation: The operation of distillation is employed for the purification of liquids from non-volatile impurities. The impure liquid is boiled in a flask and the vapours so formed are collected and condensed to give

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New answer posted

a year ago

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A
alok kumar singh

Contributor-Level 10

11.19

The different forms of cresol is formed with given molecular formula:

(I) 2-methylphenol

(II) 3-methylphenol

(III) 4-methylphenol

New answer posted

a year ago

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V
Vishal Baghel

Contributor-Level 10

Inductive effect: The inductive effect refers to the polarity produced in a molecule as a result of higher electronegativity of one atom compared to another. Atoms or groups which lose electron towards a carbon atom are said to have +I Effect. Examples of +I effect are (Electron releasing)
(CH3)2C—, (CH3)2CH—, CH3CH2— CH3— etc.
Those atoms or groups which draw electron away from a carbon atom are said to have -I Effect. Examples of -I effect are:
NO2, F, Cl, Br, I, OH etc.

Electromeric effect: The electromeric effect refers to the polarity produced in a multiple bonded compound as it is approached by a reagent.

The atom A has lost

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a year ago

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A
alok kumar singh

Contributor-Level 10

11.18

The hydroboration-oxidation reaction is a two-step reaction that converts an alkene into a neutral alcohol by the net addition of water across the double bond. The hydrogen and hydroxyl group are added in a syn addition leading to the cis configuration. Hydroboration- oxidation is an anti-Markovnikov reaction, with the hydroxyl group attaching to the less substituted carbon. In first step Addition of Hydroborate group is done and in next step, it is oxidized by hydrogen peroxide.

For example: - When propene undergoes hydroboration-oxidation reaction, then it produces propan-1-ol as product. In this reaction diborane i.e., (BH

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a year ago

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New answer posted

a year ago

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V
Vishal Baghel

Contributor-Level 10

  (a) They are structural isomers. The given compounds have the same molecular formula but they differ in the position of the functional group (here ketone group: first one at C-3 and second one at C-2 positions).

(b) They are geometrical isomers. Compounds having the same molecular formula, the same constitution, and the sequence of covalent bonds, but with the different relative position of their atoms in space are called geometrical isomers.

(c) They are resonance contributors because they differ in the position of electrons but not atoms.

New answer posted

a year ago

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P
Payal Gupta

Contributor-Level 10

4.32. 

Sigma bond

Pi bond

It is formed by axial overlap of the atomic orbitals.

It is formed by the sidewise overlap of the atomic orbitals.

The bond is quite strong.

It is a comparatively weaker bond.

Only one lobe of the p-orbitals is involved in the overlap.

Both lobes of the p-orbitals are involved in the overlap.

Electron cloud of the molecular orbital is symmetrical around the inter-nuclear axis.

The electron cloud is not symmetrical

New answer posted

a year ago

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A
alok kumar singh

Contributor-Level 10

11.17 

Due to the presence of –OH group, alcohols form hydrogen-bonds with water but hydrocarbons cannot form hydrogen-bonds with water.

Due to inter moleculer hydrogen bonding between Alcohol and water molecular they remain tightly bounded to water molecules and have higher solubility. Whereas in case of hydrocarbon there is no chance of hydrogen bonding.

New answer posted

a year ago

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V
Vishal Baghel

Contributor-Level 10

(a) Nucleophilic substitution (b) Electrophilic addition
(c) Bimolecular elimination (d) Nucleophilic substitution with rearrangement.

New answer posted

a year ago

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A
alok kumar singh

Contributor-Level 10

11.16 

Here, propanol undergoes intermolecular H-bonding because of the presence of -OH group while butane has no such property.

(intermolecular Hydrogen bonding in propanol)

Therefore, extra energy will be required to break those hydrogen bonds which in turn causes higher boiling point for propanol when compared to butane.

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