Chemistry
Get insights from 6.9k questions on Chemistry, answered by students, alumni, and experts. You may also ask and answer any question you like about Chemistry
Follow Ask QuestionQuestions
Discussions
Active Users
Followers
New answer posted
11 months agoContributor-Level 10
(b) Iron (III) hexacyanidoferrate (II) (or ferriferrocyanide) Fe4 [Fe (CN)6]3 is the correct answer.
New answer posted
11 months agoContributor-Level 10
11.26
The acidic nature of phenol can be represented by the following two reactions:-
(a) Phenols react with sodium to give sodium phenoxide, liberating H2.
(b) Phenols react with sodium hydroxide to give sodium phenoxide and water as a by-product.
The acidity of phenol is more than that of ethanol. This is because phenol after losing a proton becomes phenoxide ion which undergoes resonance and is stabilized whereas ethoxide ion does not.
The resonating structures of phenoxide ion are shown as below:
The lone pair of electrons on oxygen delocalizes into the benzene (mesomeric effect) which reduces the electron density in the O-H bon
New question posted
11 months agoNew answer posted
11 months agoContributor-Level 10
Mass of the compound = 0.468 g
Mass of barium sulphate= 0.668 g
% of sulphur = 
New answer posted
11 months agoContributor-Level 10
Mass of the compound = 0.3780 g
Mass of silver chloride = 0.5740 g
% of chlorine =
New answer posted
11 months agoContributor-Level 10
Step I: Calculation of volume of unused acid i.e. V2 =?
V1 = Volume of NAOH solution required = 60 cm3
N1 = Normality of NaOH solution = ½ N
N2 = Normality of H2SO4 = 1N
Applying N1V1 = N2V2
½ N x 60 cm3 = 1N x V2
Or V2 = 30 cm3
Step II: calculation of volume of acid used
Volume of acid added = 50 cm3
Volume of unused acid = 30 cm3
Volume of acid used = 50 – 30 = 20 cm3
Step III: Calculation of % of nitrogen
Mass of compound = 0.50 g
Volume of acid used = 20 cm3
Normality of acid used = 1 N
% of nitrogen = (1.4 x 20 x 1) / 0.50 = 56%
New answer posted
11 months agoContributor-Level 10
11.25
1-phenylethanol from a suitable alkene
The addition of water takes place according to Markovnikov rule. The alkene taken is styrene. And According to the rule, the positive charge i.e. H+ goes to the carbon of the double bond which has more number of hydrogens and the negative part i.e. OH- goes to the carbon that has less number of hydrogens. Therefore resulting the final product as 1-phenyl ethanol.
2. In the above conversion, NaOH gets dissociated into Na+ and OH-and Na+ then combines with Cl of chloromethylcyclohexane forming NaCl and thus the final product Cyclohexylmethanol is obtained.
3. In this conversion also,
New answer posted
11 months agoContributor-Level 10
Step 1: Calculation of mass of CO2 produced
Mass of compound = 0.20 g
% of carbon = 69%
i.e. 12/44 x = Mass of Carbondioxide formed / Mass of Compound = 69/100
Therefore, mass of CO2formed = (69 x 44 x 0.20) / (12 x 100) = 0.506 g
Step 2: Calculation of mass of H2O produced
Mass of compound = 0.20 g
% of hydrogen = 4.8%
i.e. 2/18 x Mass of Water Formed/Mass of Compound = 4.8/100
Therefore, mass of H2O formed = 4.8*18*0.20/2*100 = 0.0864 g
New answer posted
11 months agoContributor-Level 10
11.24
The reaction given below is:
Benzene reacts with concern. H2SO4 and undergoes the following mechanism:-
Step 1: The equilibrium produces SO3 in concentrated H2SO4, as shown below:
Step 2: SO3 is the electrophile which reacts with benzene to form arenium ion, as shown below:
Step 3: A proton is removed from the arenium ion to form benzenesulfonate ion.
Step 4: The benzenesulfonate ion accepts a proton to become benzene-sulphonic acid, as shown below:
Step 5: The benzene sulphonic acid then reacts with NaOH to give phenol as the final product, as shown below:
Taking an Exam? Selecting a College?
Get authentic answers from experts, students and alumni that you won't find anywhere else
Sign Up on ShikshaOn Shiksha, get access to
- 66k Colleges
- 1.2k Exams
- 688k Reviews
- 1850k Answers