Chemistry

4.25. Electronic configuration of ₁₃Al in ground state= 1s² 2s² 2p⁶ 3s² 3p¹

Electronic configuration of ₁₃Al in excited state = 1s² 2s² 2p⁶ 3s¹ 3p_x¹3p_y¹
Hence, hybridisation will be sp² and this makes the geometry to be Trigonal planar (in case of AlCl₃).
In AlCl^–₄, the empty 3p_z orbital is also involved. So, the hybridisation is sp³ and the shape is tetrahedral

11.11. Set (ii) is appropriate Because CH₃Br is only a nucleophile whereas CH₃ONa is nucleophile as well as strong base, so the elimination reaction can occur

11.10 During Williamson synthesis of ethers, an alkyl halide reacts with an alkoxide (ion with –ve charge on the oxygen of alcohol and + ve charge on alkali metal like Na) ion. it is an S_N2 reaction. In the reaction, alkyl halides should be least hindered. Hence, an alkyl halide is obtained from ethanol and alkoxide ion from 3-methylpentan-2-ol. The reactions are shown below:

4.23. The dipole moment of NH₃ (1.47D) is higher than the dipole moment of NF₃ (0.24D), even though the molecular geometry is pyramidal for both the molecules. In each molecule, N atom has one lone pair. F is more electronegative than H and N? F bond is more polar than N? H bond. Hence, NF₃? is expected to have much larger dipole moment than NH₃. However, reverse is true. In case of ammonia, the direction of the lone pair dipole moment and the bond pair dipole moment is same whereas in case of NF₃, it is opposite. Thus, in ammonia molecule, individual dipole moment vectors add whereas in NF₃, they cancel each other.

11.9  Phenol on mixing with chloroform and NaOH at 340K followed by Acidic hydrolysis, salicyl aldehyde is formed. When carbon tetrachloride (CCl₄) is used at the place of chloroform salicylic acid is This type of reaction is known as Reimer - Tiemann reaction.

2. The sodium phenoxide reacts with CO₂ under pressure 4-7 atm at a 400K temperature to form sodium salicylate, which on acidification yields salicylic acid. This type of reaction is known as Kolbe's

4.22. BeH₂is a linear molecular (H—Be—H), the bond angle = 180°. Be—H bonds are polar due to difference in their electronegativity but the bond polarities cancel each other. Thus, molecule has resultant dipole moment of zero

4.21. According to VSEPR theory, if CH₄ were square planar, the bond angle would be 90°. For tetrahedral structure, the bond angle is 109°28? Therefore, in square planar structure, repulsion between bond pairs would be more and thus the stability will be less.

Moreover, the orbitals of carbon in ground and excited states look as shown below. In the excited state, the electrons from 4 H atoms occupy one 2s orbital and three 2p orbitals. This results in an sp³ hybridisation, which is the hybridisation of a tetrahedral geometry