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New answer posted

a year ago

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V
Vishal Baghel

Contributor-Level 10

(a) H-COOH

CH3—COOH
CH3CH2—COOH

CH3CH2CH2—COOH
CH3CH2CH2CH2—COOH

(b) CH3COCH3
CH3COCH2CH3
CH3COCH2CH2CH3
CH3COCH2CH2CH2CH3
CH3CO (CH3)4CH3

(c) H—CH=CH2
CH3CH=CH2

CH3CH2CH=CH2
CH3CH2CH2CH=CH2
CH3CH2CH2CH2CH=CH2

New answer posted

a year ago

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A
alok kumar singh

Contributor-Level 10

11.14

Butane is the longest chain.

Propane is principle chain and substituents are numbered accordingly.

Hexane is the longest chain. There are three -OH substituents and 2 methyl groups.

-OH of phenol is numbered a 1.

Propane is the principle chain and the alkoxy group is ethyl group.

the longest chain is pentane and substituents are numbered accordingly.

In such cases, cyclo groups are named first, followed by conventional naming methods.

The cyclo group is named first, followed by conventional naming methods.

Cyclo group is named first. Pentane having a double bond is named then with the suffix -OL added to the end.

The longest chain is buta

...more

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a year ago

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V
Vishal Baghel

Contributor-Level 10

(a) 2, 2-Demethylpentane

(b) 2, 4, 7-Trimethyloctane. For two alkyl groups on the same carbon its locant is repeated twice, 2, 4, 7-locant set is lower than 2, 5, 7.
(c) 2- Chloro-4-methylpentane. Alphabetical order of substituents, (d) But-3-yn-1-ol. Lower locant for the principal functional group, i.e., alcohol.

New answer posted

a year ago

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V
Vishal Baghel

Contributor-Level 10

(a) Propylbenzene (b) 3-Methylpentanenitrite (c) 2, 5-Dimethylheptane
(d) 3-Bromo- 3-chloroheptane (e) 3-Chloropropanal (f) 2, 2-Dichloroethanol

New question posted

a year ago

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New answer posted

a year ago

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A
alok kumar singh

Contributor-Level 10

11.13

2,2,4-Trimethylpentan-3-ol

The naming of the compound usually starts with numbering the carbons in the chain. The lower set of locants are chosen for this purpose, while in this case numbering under this condition is done from the left side. Once the carbons are mentioned, the position of -OH group is numbered and -ol is added as the suffix.

 

2. 5-Ethylheptane-2,4-diol

Here the longest chain is the straight chain. For such situations, numbering should be such that the functional groups should be denoted by the smallest number. Ethyl group is named at the beginning as it's a side chain.

 

3. Butane-2,3-diol

In this system, gly

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New answer posted

a year ago

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V
Vishal Baghel

Contributor-Level 10

Single bond contains only one sigma bond and double bond contains one sigma and one pi bond.

  1. In this structure, nine single bonds and three double bonds are present. So, there are 12σ and 3π bonds present.
  2. In this structure, eighteen single bonds are present. So, there are only 18σ bonds present.
  3. In this structure, four single bonds are present. So, there are only 4σ bonds present.
  4. In this structure, four single bonds and two double bonds are present. So, there are 6σ and 2π bonds present.
  5. In this structure, five single bonds and one double bond are present. So, there are 6σ and 1π bonds present.
  6. In this structure, seven single bonds

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a year ago

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P
Payal Gupta

Contributor-Level 10

4.26. In BF3, B atom is sp2 hybridised. In NH3, N is sp3 hybridised.
After the reaction, hybridisation of B changes from sp2 to sp3, while the hybridisation of N remains the same.

New answer posted

a year ago

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A
alok kumar singh

Contributor-Level 10

When N –propyl methyl ether reacts with HBr, it forms propanol and bromomethane, n- propyl methyl ether will cleave at O . and H+ will attack at O, and Br- will attack CH +

 

2. When Ethoxybenzene Reacts with HBr, it forms Phenol and bromoethane, Ethoxybenzene cleaves at H+ will attack at O, and Br- will attack 

 

3. When nitrating mixture reacts with ethoxy benzene introduction of nitro group is occurred at para position as it will give the stable product without

 

4. As HI is a strong nucleophile it will protonate the oxygen, to form a good leaving And I- will attack at C (CH3)3+ to give tert- butyl iodide and ethanol

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