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New answer posted
a year agoContributor-Level 10
1.6. A mass percent of 69% means that 100 g of nitric acid solution contains 69 g of nitric acid by mass.
Molar mass of nitric acid HNO3= 1 + 14 + (3x16) = 63 gmol-1
New answer posted
a year agoContributor-Level 10
The difference in bond length is due to the difference in the state of hybridisation. In BF3 'B' is sp2 hybridised and in BF4– 'B' is sp3 hybridised.
New answer posted
a year agoContributor-Level 10
1.5
Since the molar mass of sodium acetate is 82.0245 g mol-1.
⇒ 1 mol of CH3COONa has a mass = 82.0245 g
∴Mass of sodium acetate (CH3COONa) required to make 500 ml of 0.375 molar aqueous solution
= 0.375 x 0.5 mol x 82.0245 g mol-1
= 15.3795 g = 15.380 g
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a year agoContributor-Level 10
- PbCl2 + Cl2→ PbCl4.
This is because Pb can show +2 oxidation state more easily than +4 due to inert pair effect. - PbCl4→ PbCl2 + Cl2
Because Pb2+ is more stable than Pb4+ due to inert pair effect. - PbI4does not exist because I- ion being a powerful reducing agent reduces Pb4+ ion to Pb2+ ion in solution.
Pb4+ + 2I– → Pb2+ + I2
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a year agoContributor-Level 10
Diamond has a crystalline lattice where each carbon atom undergoes sp3 hybridisation and linked to four other carbon atoms by using hybridised orbitals in tetrahedral fashion. The C–C bond length is 154 pm. The structure extends in space and produces a rigid three- dimensional network of carbon atoms. It is very difficult to break extended covalent bonding and, therefore, diamond is a the hardest substance on the earth.
Graphite has layered structure in which the layers are held by van there Waals forces and distance between two layers is 340 pm. Each layer is composed of planar hexagonal rings of carbon atoms. C—C bond length
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a year agoContributor-Level 10
1.4 In order to answer the question, we need to know the balanced equation for the combustion of carbon in dioxygen/air, which can be written as:
C (s) + O2 (g) à CO2 (g)
(i) We can see from the above equation,
1 mole of carbon reacts with 1 mole of oxygen to produce 1 mol of carbon dioxide.
In air, combustion is complete.
Therefore, CO2 produced from combustion of 1 mole of carbon= Molar mass of CO2= 44 g
(ii) As only 16 g of dioxygen is available, it can combine only with 0.5 mole of carbon, i.e., dioxygen is the limiting reactant.
Hence, CO2 produced = 22 g
Here, dioxygen acts as the limiting reagent.
(iii) Here again, dioxygen is
New answer posted
a year agoContributor-Level 10
1.3 We are given that the percentage of iron by mass is 69.9% and the percentage of oxygen by mass is 30.1%.
Since we have relative moles of both elements, we can calculate the simpler molar ratio of iron to oxygen
= 1.25: 1.88
Divide by the smaller value to both
= 1.25/1.25: 1.88/1.25
= 1: 1.5
= 2: 3
So, now we can write the empirical formula of iron oxide as Fe2O3.
New question posted
a year agoNew answer posted
a year ago11.9. What are electron deficient compounds? Are BCl3 and SiCl4 electron deficient species? Explain.
Contributor-Level 10
Electron deficient compounds are those in which the central atom in their molecule has the tendency to accept one or more electron pairs. They are also known as Lewis acid. BCl3 and SiCl4 both are electron deficient species.
Since, in BCl3, B atom has only six electrons. Therefore, it is an electron deficient compound.
In SiCl4 the central atom Si has 8 electrons but it can expand its covalency beyond 4 due to the presence of d-orbitals.
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