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Class 11th Physics

The initial mass of a rocket is 1000kg. Calculate at what rate the fuel should be burnt so that the rocket is given an acceleration of 20ms^-². The gases come out at a relative speed of 500ms^-¹ with respect to the rocket: [Use g = 10m/s²]

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Vishal Baghel

Contributor-Level 10

$V_{r e l} \frac{d m}{d t} - m g = F_{e x t}$

=>500 $\frac{d m}{d t} - 1000 * 10 = 1000 * 20$

$\frac{d m}{d t} = 60 k g / s$

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3 months ago

Class 11th Mechanical Properties of Fluids

Two narrow bores of diameter 5.0mm and 8.0 mm are joined together to form a U-shaped tube open at both ends. If this U-tube contains water, what is the difference in the level of two limbs of the tube.

[Take surface tension of water T = 7.3 * 10^-² Nm^-¹, angle of contact = 0, g = 10 ms^-² and density of water = 1.0 * 10³ kg m^-³]

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Vishal Baghel

Contributor-Level 10

P_B – P_A = $ρ g h$

$\Rightarrow (P_{0} - \frac{2 T}{r^{2}}) - (P_{0} - \frac{2 T}{r_{1}}) = ρ g h$

$h = \frac{2 T (\frac{1}{r_{1}} - \frac{1}{r_{2}})}{ρ g}$

$= \frac{2 * 7.3 * 1 0^{- 2} * (\frac{1}{2.5 * 1 0^{- 3}} - \frac{1}{4 * 1 0^{- 3}})}{1000 * 10}$

$\begin{array}{l} = 2.19 * 1 0^{- 3} m \\ = 2.19 m m \end{array}$

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Class 11th Physics Oscillations

If the length of the pendulum in pendulum clock increases by 0.1%, then the error in time per day is

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alok kumar singh

Contributor-Level 10

$\frac{Δ T}{T} = \frac{1}{2} \frac{Δ l}{l}$

$\Rightarrow Δ T = \frac{1}{2} * \frac{0.1}{100} * 24 * 60 * 60 = 43.2 s$

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Class 11th Physics

If a book is at rest on a table, does Newton's First Law mean no forces are acting on it?

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Syed Aquib Ur Rahman

Contributor-Level 10

No, that's a common misconception about force in any object at rest. According to Newton's First Law, zero acceleration means zero net force. That does not mean zero force. A book on a table is at rest because two forces act on it. Gravity pulls it down. The table exerts an equal upward normal force. These forces balance each other, so the net force is zero. This can also be proved with Sir Isaac Newton's laws of motion. The 2nd Law implies that the book is not accelerating, so net force is zero. The third law of action and reaction states that the book pulls the table down with a force equal to its weight, as action. The table pushes

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Class 11th Physics

The solid cylinder of length 80cm and mass M has a radius of 20cm. Calculate the density of the material used if the moment of inertial of the cylinder about an axis CD parallel to AB as shown in figure is 2.7 kg m²

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alok kumar singh

Contributor-Level 10

$l_{C D} = \frac{1}{2} M r^{2} + M {(\frac{L}{2})}^{2}$

$\Rightarrow 2.7 = M (\frac{0 . 2^{2}}{2} + \frac{0 . 8^{2}}{4})$

M = 15 kg

Density, $ρ = \frac{M}{π r^{2} L} = \frac{15}{3.14 * 0 . 2^{2} * 0.8} = 1.49 * 1 0^{2} k g / m^{3}$

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3 months ago

Class 11th Physics Motion in Plane

A bomb is dropped by a fighter plane flying horizontally. To an observer sitting in the plane, the trajectory of the bomb is a:

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alok kumar singh

Contributor-Level 10

Horizontal component of velocity of bomb equals to the velocity of plane. So, bomb and plane are in same vertical line always.

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3 months ago

Class 11th Laws of Motion

A particle of mass m is suspended form a ceiling through a string of length L. The particle movies in a horizontal circle of radius r such that $r = \frac{L}{\sqrt[]{2}} .$ The speed of particle will be:

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alok kumar singh

Contributor-Level 10

$T s i n θ = \frac{m v^{2}}{r}$

T cosθ = mg

$t a n θ = \frac{v^{2}}{r g}$

$\Rightarrow v = \sqrt[]{r g}$

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3 months ago

Class 11th Physics

For $z = a^{2} x^{3} y^{\frac{1}{2}},$ where 'a' is a constant. If percentage error in measurement of 'x' and 'y' are 4% and 12% respectively, then the percentage error for 'z' will be…………%

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Raj Pandey

Contributor-Level 9

$\frac{Δ z}{z} * 100 = 3 \frac{Δ x}{x} * 100 + \frac{1}{2} \frac{Δ y}{y} * 100$

$= 3 * 4 + \frac{1}{2} * 12$

$= (12 + 6) %$

$= 18 %$

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3 months ago

Class 11th Chemistry

A cylindrical container of volume 4.0 * 10^-3 m³ contains one mole of hydrogen and two moles of carbon dioxide. Assume the temperature of the mixture is 400K. The pressure of the mixture of gases is : [Take gas constant as 8.3J mol^-1 K^-1]

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alok kumar singh

Contributor-Level 10

$P = \frac{n R T}{V} = \frac{(1 + 2) * 8.3 * 400}{4.0 * 1 0^{? 3}} = 24.9 * 1 0^{5} P a$

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Class 11th Physics

Match List-I with List-II:

List – I List – II

(a) Magnetic Induction

...more

Match List-I with List-II:

List – I List – II

(a) Magnetic Induction (i) ML²T^-²A^-¹

(b) Magnetic Flux (ii) $M^{0} L^{- 1} A$

(c) Magnetic Permeability (iii) $M T^{- 2} A^{- 1}$

(d) Magnetization (iv) MLT^-²A^-²

Choose the most appropriate answer form the options given below:

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alok kumar singh

Contributor-Level 10

$[B] = M T^{- 2} A^{- 1}$

$[?] = M L^{2} T^{- 2} A^{- 1}$

$[μ] = M L T^{- 2} A^{- 2}$

$[M] = M^{0} L^{- 1} A$

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