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8 months ago

Class 11th Physics Oscillations

The metallic bob of simple pendulum has the relative density. 5 The time period of this pendulum is 10 s. If the metallic bob is immersed in water, then the new time period becomes $5 \sqrt[]{x} s .$ The value of x will be_______.

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alok kumar singh

Contributor-Level 10

g_eff = g – $(\frac{ρ_{w}}{ρ_{b}}) g$

$T = 2 π \sqrt[]{\frac{l}{g}}$

$T' = 2 π \sqrt[]{\frac{l}{g_{e f f}}}$

$\Rightarrow T' = \sqrt[]{\frac{5}{4}} T$

= $\sqrt[]{\frac{5}{4}} * 10$

= $5 \sqrt[]{5} s e c$

So, x = 5

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New answer posted

8 months ago

Class 11th Physics

A solid cylinder length is suspended symmetrically through two massless strings, as shown in the figure. The distance from the initial rest position, the cylinder should by unbinding the strings to achieve a speed of 4 ms^-¹, is__________cm. (take g = 10 ms^-²)

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Vishal Baghel

Contributor-Level 10

.From conservation of energy

mgh = $\frac{1}{2} m v^{2} + \frac{1}{2} l ω^{2}$ $\frac{}{}^{} \frac{}{}^{}$

$\Rightarrow m g h = \frac{1}{2} m v^{2} + \frac{1}{2} \frac{m R^{2}}{2}$

10 h = $\frac{16}{2} + \frac{16}{4}$ $\frac{}{} \frac{}{}$

h = 1.2 m = 120 cm

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New answer posted

8 months ago

Class 11th Mechanical Properties of Fluids

A spherical soap bubble of radius 3cm is formed inside another spherical soap bubble of radius 6cm. If the internal pressure of the smaller bubble of radius 3cm in the above system is equal to the internal pressure of the another single soap bubble of radius r cm.

The value of r is___________.

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Vishal Baghel

Contributor-Level 10

$P_{2} - P_{06} = \frac{4 T}{6} & P_{1} - P_{2} = \frac{4 T}{3}$

$P_{1} - P_{0} = \frac{4 T}{2} = \frac{4 T}{r}$

r = 2cm

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New answer posted

8 months ago

Class 11th Physics Mechanical Properties of Solids

The speed of a transverse wave passing through a string of length 60 cm and mass 10g is 60 ms^-1. The area of cross-section of the wire is 2.0 mm² and its Young's modulus is 1.2 * 10¹¹ Nm^-2. The extension of the wire over its natural length due to its tension will be x * 10^-5 m. The value of x is________.

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alok kumar singh

Contributor-Level 10

m = 10g

$l = 50 c m$

A = 2mm²

Y = 1.2 * 10¹¹N/m²

$Δ x = x * 1 0^{- 5} m$

As, $\frac{T}{A} = Y \frac{Δ x}{l}$

$Δ x = \frac{T l}{A Y}$

$T l = V^{2} m$

= $\frac{V^{2} m}{A Y}$

$= \frac{3600 * 10 * 1 0^{- 3}}{2 * 1 0^{- 6} * 1.2 * 1 0^{11}} = \frac{1800 * 1 0^{- 3} * 1 0^{6}}{1.2}$

$= \frac{18}{12} * 1 0^{- 4} = \frac{3}{2} * 1 0^{- 4} = 15 * 1 0^{- 5} m$

So, x = 15

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New answer posted

8 months ago

Class 11th Waves

A wire of length 30cm, stretched between rigid supports, has it's n^th and (n + 1)^th harmonics at 400Hz and 450Hz, respectively, If tension in the string is 2700N, it's linear mass density is ____________kg/m.

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Vishal Baghel

Contributor-Level 10

$\frac{n v}{0.6} = 400 & \frac{(n + 1) v}{0.6} = 450$

$\Rightarrow [\frac{0.6 * 450}{v} + 1]$ $\frac{v}{0.6} = 450$

v = 30

$\Rightarrow \sqrt[]{\frac{T}{μ}} = 30$

^{$\Rightarrow \frac{2700}{μ} = 900$}

^{$μ = 3$}

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New answer posted

8 months ago

Class 11th Physics Mechanical Properties of Fluids

The velocity of a small ball of mass 0.3g and density 8 g/cc when dropped in a container filled with glycerine becomes constant after some time. If the density of glycerine is 1.3 g/cc, then the value of viscous force acting on the ball will be x * 10^-4 N, value of x is________. [use g = 10 m/s²]

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alok kumar singh

Contributor-Level 10

m = 0.3g density, $ρ_{(b a l l)} = 8 g / c c$ $∴ V = \frac{m}{ρ} = \frac{0.3}{8} c c$

$ρ_{g l y c e r e n e} = 1.3 g / c c = 1.3 * 1 0^{3} k g / m^{3}$

F_v + F_B = mg.

=F_v = mg – F_B = .3 * 10^-3 * 10 – 1.3 * $\frac{0.3}{8} * 1 0^{- 6} * 10 * 1 0^{3}$

$= 3 * 1 0^{- 3} - \frac{. 39}{8} * 1 0^{- 2} = 3 * 1 0^{- 3} - . 5 * 1 0^{- 3}$

= 2.5 * 10^-3N

= 25 * 10^-4N

x = 25

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New answer posted

8 months ago

Class 11th Mechanical Properties of Solids

In an experiment to determine the Young's modulus, steel wires of five different lengths (1, 2, 3, 4, and 5m ) but of same cross section (2 mm²) were taken and curves between extension and load were obtained. The slope (extension / load) of the curves were plotted with the wire length and the following graph is obtained. If the Young's modulus of given steel wires is x * 10¹¹ Nm^-², then the value of x is________.

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Vishal Baghel

Contributor-Level 10

Slope = $\frac{Δ L / W}{L} = \frac{Δ L / L}{W} = \frac{1}{Y A}$ $\frac{}{} \frac{}{} \frac{}{}$

$Y = \frac{1}{(S l o p e) A}$

$Y = \frac{1}{(2 * 1 0^{- 6}) (0.25 * 1 0^{- 5})}$

$Y = 2 * 1 0^{11} N / m^{2}$

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New answer posted

8 months ago

Class 11th Physics Mechanical Properties of Solids

A metal wire of length 0.5 m and cross-sectional area 10^-4 m² has breaking stress 5 * 10⁸ Nm^-2. A block of 10 kg is attached at one of the string and is rotating in a horizontal circle. The maximum linear velocity of block will be ________ ms^-1.

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alok kumar singh

Contributor-Level 10

$l = 0.5 m$

A $^{}^{}$ $= 1 0^{- 4} m^{2}$

Breaking stress, $\frac{F}{A} = 5 * 1 0^{8} N / m^{2}$ $\frac{}{}^{}^{}$

$F = 5 * 1 0^{8} * 1 0^{- 4} N$

F = 5 * 104N

T = $\frac{m V^{2}}{l} \Rightarrow V_{(m a x)}^{2} = = \frac{T l}{m}$ $\frac{^{}}{}_{}^{} \frac{}{}$

$V_{m}^{2} = 2.5 * 1 0^{3}$

V_max = 50m/s

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New answer posted

8 months ago

Class 11th Physics Mechanical Properties of Fluids

A tube of length 50 cm is filled completely with an incompressible liquid of mass 250g closed both ends. The tube is then rotated in horizontal plane about one of its ends with a uniform angular velocity $z \sqrt[]{F} r a d s^{- 1} .$ If F be the force exertaed by the liquid at the other end then the value of x will be __________.

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alok kumar singh

Contributor-Level 10

$ω = x \sqrt[]{F} r a d / 5$

As, F = $m ω^{2} \frac{L}{2}$

$\Rightarrow F = \frac{m L}{2} (x^{2} F) \Rightarrow x^{2} = \frac{2}{m L} = \frac{2}{\frac{1}{4} * \frac{1}{2}} = 16$

$∴ x = 4$

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New answer posted

8 months ago

Class 11th Chemical Bonding and Molecular Structure

Why does MgO have a higher melting point than NaCl ?

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nitesh singh

Contributor-Level 10

Higher melting point means more energy is required to break the ionic bond. Since the ionic bonds in MgO are stronger than in NaCl due to various reasons, It have higher melting and even boiling point. Reasons are listed below:

In MgO, Magnesium and oxygen ions carry a +2 and -2 charge while sodium and in NaCl, chlorine ions carry a +1 and -1 charge. Due to higher charges more electrostatic attraction is involved.
The smaller ionic radius of Mg2+ are smaller compared to Na+, makes the bond stronger in MgO.
Due to larger elctrostatic force and smaller ionic radius, ionic bond in MgO are stronger, resulting in higher lattice energy.
The stro

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