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New answer posted

6 months ago

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P
Payal Gupta

Contributor-Level 10

This is a short answer type question as classified in NCERT Exemplar

On increasing the pressure slightly the gas 'A' liquefies but gas B does not liquify even on applying high pressure until it is cooled at same  conditions of temperature and pressure  filled in equal capacity containers it happens because the gas 'A' being at the  critical temperature liquifies on slightly increasing the pressure and  gas 'B' being at higher temperature than critical temperature does not liquifies even on applying high pressure until it is cooled.

New answer posted

6 months ago

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P
Payal Gupta

Contributor-Level 10

This is a short answer type question as classified in NCERT Exemplar

A gas that  follows Boyle's law, Charle's law and Avogadro's law is called an ideal gas.

Real gas behaves ideal under low pressure and high temperature. Under these conditions, the intermolecular interactions are minimum.

New answer posted

6 months ago

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Payal Gupta

Contributor-Level 10

This is a short answer type question as classified in NCERT Exemplar

The molar volume of both nitrogen and argon at 273.15 K and 1 atm is 22.4 L.

At STP (1 atm pressure and 273.15 K or 00 C), the molar volume i.e the volume of 1 mole gas is 22.4L. 

New answer posted

6 months ago

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P
Payal Gupta

Contributor-Level 10

This is a short answer type question as classified in NCERT Exemplar

(a) HCl, HBr and HI have dipole-dipole and london dispersion  interaction   whereas HF has hydrogen bonding in addition (due to the high electronegativity of the F atom).

(b) The electronegativity decreases from Cl, Br and I so the dipole-dipole interaction will also decrease as HCl > HBr > HI  and it is contrary to the boiling point order which is HCl < HBr < HI. This confirms that the London interaction is predominant.

(c) F atom has the highest electronegativity so it has hydrogen bonding interaction in addition to   dipole-dipole and london dispersion  interaction which leads to the highest boiling poi

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New answer posted

6 months ago

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P
Payal Gupta

Contributor-Level 10

This is a short answer type question as classified in NCERT Exemplar

The factors that determine the states of matter are:

1. Temperature

2. Pressure

3. Mass and volume

New answer posted

6 months ago

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P
Payal Gupta

Contributor-Level 10

This is a short answer type question as classified in NCERT Exemplar

Physical state of ice, water and steam are very different but the chemical composition of water in all the three states is H2O.

New answer posted

6 months ago

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P
Payal Gupta

Contributor-Level 10

This is a short answer type question as classified in NCERT Exemplar

  (a) the greatest volume is occupied by CH4 and

(b) the smallest volume by NO

According to Avagadro's Law,

Volume of 1 mole of a gas at STP   =   22.4 L

Now, we know,

1 mole  =     Molar mass

∴   Volume of 28g mol-1 of CO at STP   =   22.4 L

So, Volume of 1 g  of CO at STP   =   22.4 L / 28 g mol-1

Similarly,  

Volume of 1 g  of  H2O at STP   =   22.4 L / 18 g mol-1

Volume of 1 g  of  CH4 at STP   =   22.4 L / 16 g mol-1              (

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New question posted

6 months ago

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New answer posted

6 months ago

0 Follower 4 Views

A
alok kumar singh

Contributor-Level 10

This is a Long Answer type Questions as classified in NCERT Exemplar

Explanation – as body moving with uniform acceleration a=0

The sum of forces is zero F1+F2+F3=0

a)let F1, F2, F3 be the three forces passing through the point . let F1and F2 be in the plane A

so F3 =- (F1+F2) so F3 is also in plane A.

b)consider the torque of the forces about P . since all the forces pass through P the torque is zero

torque = OP (F1+F2+F3)

since F1+F2+F3=0 so torque =0

New answer posted

6 months ago

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A
alok kumar singh

Contributor-Level 10

This is a Short Answer type Questions as classified in NCERT Exemplar

Explanation -initial speed of coin u= 20m/s

Acceleration of elevator =2m/s2 acceleration due to gravity = 10m/s2

Effective acceleration =g+a=12m/s2

We know that v=u +at

0= 20+ (-12)t

So t= 20/12=5/3 s

Time of ascent = time of descent

Total time coin fall back into hand = (5/3+5/3)=10/3s=3.33s

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