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4 months ago

Class 11th Chemistry NCERT Exemplar Solutions Class 11th Chapter Five

The variation of vapour pressure of different liquids with temperature is shown in Fig. 5.6.

i. Calculate graphically boiling points of liquids A and B.

ii. If we take liquid C in a closed vessel and heat it continuously. At what temperature will it boil?

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Payal Gupta

Contributor-Level 10

This is a long answer type question as classified in NCERT Exemplar

i. The boiling points of liquid A is approximately 315 K and of liquid B is approximately 345 K (shown below graphically).

ii. Liquid C in a closed vessel will not boil as the pressure keeps on increasing.

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4 months ago

Class 11th Chemistry NCERT Exemplar Solutions Class 11th Chapter Five

Isotherms of carbon dioxide at various temperatures are represented in Fig. 5.5. Answer the following questions based on this figure.

i. In which state will CO₂ exist between the points a and b at temperature T₁?

ii. At what point will CO₂ start liquefying when temperature is T₁?

iii. At what point will CO₂ be completely liquefied when temperature is T₂?

iv. Will condensation take place when the temperature is T₃.

v. What portion of the isotherm at T₁ represents liquid and gaseous CO₂ at equilibrium?

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Payal Gupta

Contributor-Level 10

This is a long answer type question as classified in NCERT Exemplar

i. CO₂ will exist in a gaseous state between the points a and b at temperature T₁.

ii. At point b, CO₂ will start liquefying when temperature is T₁

iii. At point g, CO₂ will be completely liquefied when temperature is T₂

iv. No, the condensation will not take place when the temperature is T₃ because T₃ > T_c.

v. Between b and c of the isotherm at T₁, represents the liquid and gaseous CO₂ at equilibrium.

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4 months ago

Class 11th Chemistry NCERT Exemplar Solutions Class 11th Chapter Five

Assertion (A): Liquids tend to have maximum number of molecules at their surface.

Reason (R) : Small liquid drops have spherical shape.

(i) Both A and R are true and R is the correct explanation of A.

(ii) Both A and R are true but R is not the correct explanation of A.

(iii) A is true but R is false.

(iv) A is false but R is true.

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Payal Gupta

Contributor-Level 10

This is a assertion and reason answer type question as classified in NCERT Exemplar

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4 months ago

Class 11th Physics NCERT Exemplar Solutions Class 11th Chapter Five

A rectangular box lies on a rough inclined surface. The co-efficient of friction between the surface and the box is µ. Let the mass of the box be m.

(a) At what angle of inclination θ of the plane to the horizontal will the box just start to slide down the plane?

(b) What is the force acting on the box down the plane, if the angle of inclination of the plane is increased to α θ > ?

(c) What is the force needed to be applied upwards along the plane to make the box either remain stationary or just move up with uniform speed?

(d) What is the force needed to be applied upwards along the plane to make the box move up the plane with

...more

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alok kumar singh

Contributor-Level 10

This is a Long Answer type Questions as classified in NCERT Exemplar

Explanation -for the box to just starts sliding down mg

sin $θ = t = μ N = μ m g c o s θ$

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4 months ago

Class 11th Chemistry NCERT Exemplar Solutions Class 11th Chapter Five

Assertion (A): At critical temperature liquid passes into gaseous state imperceptibly and continuously.

Reason (R) : The density of liquid and gaseous phase is equal to critical temperature.

(i) Both A and R are true and R is the correct explanation of A.

(ii) Both A and R are true but R is not the correct explanation of A.

(iii) A is true but R is false.

(iv) A is false but R is true.

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Payal Gupta

Contributor-Level 10

This is a assertion and reason answer type question as classified in NCERT Exemplar

(i) Both A and R are true and R is the correct explanation of A.

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4 months ago

Class 11th Chemistry NCERT Exemplar Solutions Class 11th Chapter Five

Assertion (A): Gases do not liquefy above their critical temperature, even on applying high pressure.

Reason (R) : Above critical temperature, the molecular speed is high and intermolecular attractions cannot hold the molecules together because they escape because of high speed.

(i) Both A and R are true and R is the correct explanation of A.

(ii) Both A and R are true but R is not the correct explanation of A.

(iii) A is true but R is false.

(iv) A is false but R is true.

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Payal Gupta

Contributor-Level 10

This is a assertion and reason answer type question as classified in NCERT Exemplar

(i) Both A and R are true and R is the correct explanation of A.

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4 months ago

Class 11th Chemistry NCERT Exemplar Solutions Class 11th Chapter Five

Assertion (A): The temperature at which vapour pressure of a liquid is equal to the external pressure is called boiling temperature.

Reason (R) : At high altitude atmospheric pressure is high.

(i) Both A and R are true and R is the correct explanation of A.

(ii) Both A and R are true but R is not the correct explanation of A.

(iii) A is true but R is false.

(iv) A is false but R is true.

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Payal Gupta

Contributor-Level 10

This is a assertion and reason answer type question as classified in NCERT Exemplar

option (iii). A is true but R is false.

At high altitude, the atmospheric pressure is low.

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4 months ago

Class 11th Physics NCERT Exemplar Solutions Class 11th Chapter Five

There are four forces acting at a point P produced by strings as shown in Fig. , which is at rest. Find the forces F₁ and F₂

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alok kumar singh

Contributor-Level 10

This is a Long Answer type Questions as classified in NCERT Exemplar

Explanation- on resolving forces into rectangular components in equilibrium forces (F₁+1/ $\sqrt[]{2}$ )N are equal to $\sqrt[]{2} N$ and F₂ is equal to ( $\sqrt[]{2} + 1 / \sqrt[]{2}$ )N

F₁+1/ $\sqrt[]{2}$ = $\sqrt[]{2}$

F₁= $\sqrt[]{2} - 1 / \sqrt[]{2}$ = $\frac{2 - 1}{\sqrt[]{2}} = \frac{1}{\sqrt[]{2}} = 0.707 N$

F₂= $\sqrt[]{2} + \frac{1}{\sqrt[]{\sqrt[]{2}}} = \frac{2 + 1}{\sqrt[]{2}} = \frac{3}{\sqrt[]{2}} = 2.121 N$

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4 months ago

Class 11th Chemistry NCERT Exemplar Solutions Class 11th Chapter Five

Assertion (A): At constant temperature, pV vs V plot for real gases is not a straight line.

Reason (R) : At high pressure all gases have Z > 1 but at intermediate pressure most gases have Z < 1.

(i) Both A and R are true and R is the correct explanation of A.

(ii) Both A and R are true but R is not the correct explanation of A.

(iii) A is true but R is false.

(iv) A is false but R is true.

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Payal Gupta

Contributor-Level 10

This is a assertion and reason answer type question as classified in NCERT Exemplar

At constant temperature, the pV vs V plot for real gases is not a straight line because there is intermolecular attraction present in real gases which is absent in ideal gases; hence ideal gases form a straight line in the pV vs V plot at constant temperature.

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4 months ago

Class 11th Physics NCERT Exemplar Solutions Class 11th Chapter Five

A cricket bowler releases the ball in two different ways

(a) Giving it only horizontal velocity, and

(b) Giving it horizontal velocity and a small downward velocity.

The speed vs at the time of release is the same. Both are released at a height H from the ground. Which one will have greater speed when the ball hits the ground? Neglect air resistance.

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alok kumar singh

Contributor-Level 10

This is a Long Answer type Questions as classified in NCERT Exemplar

Explanation – horizontal velocity u_x= v_s

During projectile motion horizontal velocity remains unchanged

V_x=u_x=v_s

In vertical direction v_y²= u_y²+2gH

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