Class 11th

From F.B. Ds of

$9kg\to 90-T_1=9a\dots .\left(1\right)$

$6kg\to T_1-T_2=6a\dots ..\left(2\right)$

$5kg\to T_2-50=5a\dots ..\left(3\right)$

$\left(1\right)+\left(2\right)+\left(3\right)$

$40=20a?a=2m/s^2$

$a_{cp}=\frac{v^2}{r}=\frac{{\left(\sqrt[]{3gl}\right)}^2}{l}=\frac{3gl}{l}=3g$

Kinetic energy $=\frac{1}{2}I{\omega }^2$ , and for ring   $I=m{r}^2$

Hence $KE=\frac{1}{2}m{r}^2{\omega }^2$

$M=0.5kg$

$V=1.5m/s$

$K=50N/m$

Maximum Compression of the spring

$\frac{1}{2}m{v}^2=\frac{1}{2}k{x}^2$

$k{x}^2=m{v}^2$
$x=v\sqrt[]{\frac{m}{k}}=1.5\sqrt[]{\frac{0.5}{50}}.$

$x=0.15m$

In a number without decimal, trailing zeros are insignificant. If a number has a decimal, then preceding zeros are insignificant.

Hence, in 40.40 all zeros are significant

The three fundamental laws of chemistry are - Law of Definite Proportions, Law of Conservation of Mass, and Law of Multiple Proportions.

$kx=mg-F_{up}$

$kx=mg-\frac{md}{D}g$

$x=\frac{mg}{k}\left(1-\frac{d}{D}\right)$

The three types of chemical bonds are - ionic, metallic and covalent bonds. When the electrons transfer between the atoms, they form the Ionic bonds by producing charged ions that are attracted to each other. When atoms share electrons, covalent bonds are created. When metal atoms share a sea of delocalized electrons, metallic bonds get created.

Rate of burning of fuel $\left(\frac{dm}{dt}\right)=1kg/s$  and velocity of ejected fuel

$\left(v\right)=60km/s$

$=60*10^{3}m/s.$  

Forcev =  Rate of change of momentum

$=\frac{dp}{dt}=\frac{d\left(m\nu \right)}{dt}=v\frac{dm}{dt}=\left(60*10^3\right)*1$

  $=60000$ N.

The chemical bonds can be primary or strong bonds such as ionic, covalent, and metallic bonds. It can also be the secondary or weak bonds like hydrogen bonding, London dispersion force, and dipole interactions.