Class 11th

Get insights from 8k questions on Class 11th, answered by students, alumni, and experts. You may also ask and answer any question you like about Class 11th

Follow Ask Question
8k

Questions

0

Discussions

37

Active Users

0

Followers

New answer posted

6 months ago

0 Follower 1 View

P
Payal Gupta

Contributor-Level 10

5.15. Molar mass of O2 = 32 g/mol

It means, 8 g of O2 has 8/32 mol = 0.25 mol

Molar mass of H2 = 2 g/mol

It means, 4 g of H2 has 4/2 mol = 2 mol

Therefore, total number of moles, n = 2 + 0.25 = 2.25 mol

Given, V = 1dm3, T = 27°C = 300 K, R = 0.083 bar dm3 K-1 mol-1

Applying PV = nRT,

P = nRT / V

   = (2.25) (0.083 bar dm3 K-1 mol-1) (300 K) / (1dm3)

   = 56.025 bar

New answer posted

6 months ago

0 Follower 3 Views

P
Payal Gupta

Contributor-Level 10

5.14. Time taken to distribute 1010 wheat grains = 1s

Time taken to distribute Avogadro number of wheat grains = (1s x 6.022 x 1023) / 1010

= 6.022 x 1013 s

= (6.022 x 1013 / 60 x 60 x 24 x 365) year

= 1.9 x 106 years

New answer posted

6 months ago

0 Follower 2 Views

P
Payal Gupta

Contributor-Level 10

5.13. Molecular mass of N= 28g
28 g of N2 has No. of molecules = 6.022 x 1023 

1.4 g of N2 has No. of molecules = (6.022 x 1023 x 1.4 g)/28 g= 3.011 x 1022 molecules.
Atomic No. of Nitrogen (N) = 7
1 molecule of N2 has electrons = 7 x 2 = 14
3.011 x 1022 molecules of N2 have electrons= 14 x 3.011 x 1022= 4.215 x1023 electrons.

New answer posted

6 months ago

0 Follower 1 View

P
Payal Gupta

Contributor-Level 10

5.12. Given,

P= 3.32 bar

V= 5 dm3 

n= 4 mol

R= 0.083 bar dm3 K-1 mol-1

PV = nRT

Or T = PV / nR = 3.32 x 5 dm3 / (4.0 mol x 0.083 bar dm3 K-1 mol-1)

         = 50 K

New answer posted

6 months ago

0 Follower 2 Views

P
Payal Gupta

Contributor-Level 10

9.56. Dihydrogen is prepared from water by the action of alkali metals like Na and K which is a strong reducing agent.

2Na + 2H2O → 2NaOH + H2

2K + 2H2O → 2KOH + H2

New answer posted

6 months ago

0 Follower 1 View

P
Payal Gupta

Contributor-Level 10

9.55. 1. High heat of combustion.

2. It is pollution free.

New answer posted

6 months ago

0 Follower 1 View

P
Payal Gupta

Contributor-Level 10

9.54. Water which does not produce lathers with soap is known as hard water. Hardness is due to the presence of bicarbonates, sulphates and chlorides of Ca2+ and Mg2+.

On boiling, the bicarbonates of calcium and magnesium decompose to insoluble carbonate which can be removed by filtration.

New answer posted

6 months ago

0 Follower 3 Views

P
Payal Gupta

Contributor-Level 10

9.53. In water molecule, O is SP3 hybridized. Due to stronger lone pair-lone pair repulsion than bond pair-bond pair repulsions, the H-O-H bond angle decreases from 109.5° to 104.5°. Thus, water is bent molecule.

New answer posted

6 months ago

0 Follower 1 View

P
Payal Gupta

Contributor-Level 10

9.52. Many transition and inner-transition metals absorb hydrogen into the interstices of their lattices to yield metal like hydrides also called the interstitial hydrides. These hydrides are generally non stoichiometric and their composition vary with temperature and pressure.
For example, TiH1.73, CeH2.7

Two uses of interstitial hydrides are:

(i) In the storage of H2.

(ii) Catalyst for hydrogenation reaction.

New answer posted

6 months ago

0 Follower 1 View

P
Payal Gupta

Contributor-Level 10

9.51. Dihydrogen, under certain reaction conditions, combines with almost all elements, except noble gases, to form binary compounds, called hydrides. If 'E' is the symbol of an element then hydride can be expressed as EHx (e.g., MgH2) or EmHn (e.g., B2H6).

The hydrides are classified into three categories:

(i) Ionic or saline or saltlike hydrides

(ii) Covalent or molecular hydrides

(iii) Metallic or non-stoichiometric hydrides

Get authentic answers from experts, students and alumni that you won't find anywhere else

Sign Up on Shiksha

On Shiksha, get access to

  • 65k Colleges
  • 1.2k Exams
  • 679k Reviews
  • 1800k Answers

Share Your College Life Experience

×
×

This website uses Cookies and related technologies for the site to function correctly and securely, improve & personalise your browsing experience, analyse traffic, and support our marketing efforts and serve the Core Purpose. By continuing to browse the site, you agree to Privacy Policy and Cookie Policy.