Class 11th
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New answer posted
6 months agoContributor-Level 10
The structures of cis- and trans-isomer of hex-2-ene are:

The boiling point of a molecule depends upon dipole-dipole interactions. Since cis-isomer has higher dipole moment, therefore, it has higher boiling point.
New answer posted
6 months agoContributor-Level 10
3.40. Within a period, the oxidising character increases from left to right. Therefore, among F, O and N, oxidising power decreases in the order: F > O > N. However, within a group, oxidising power decreases from top to bottom. Thus, F is a stronger oxidising agent than Cl. Further because O is more electronegative than Cl, therefore, O is a stronger oxidising agent than Cl. Thus, overall decreasing order of oxidising power is: F > O > Cl > N, i.e., option (b) is correct.
New answer posted
6 months agoContributor-Level 10
A combustion reaction is a reaction in which a substance reacts with oxygen gas, there is a formation of carbon dioxide, water with the evolution of light and heat.
(i) 2C4H10 (g) +13 O2 (g)?8CO2 (g)+10H2O (g) + Heat
(ii) 2C5H10 (g) +15 O2 (g)?10CO2 (g)+10H2O (g) + Heat
(iii) 2C6H10 (g) +17 O2 (g)?12CO2 (g)+10H2O (g) + Heat

New answer posted
6 months agoContributor-Level 10
The ozonolysis of 4-Ethylhex-3-ene gives propanal and pentan-3-one.
The structural formula of the alkene (4-Ethylhex-3-ene) is as shown.



New answer posted
6 months agoContributor-Level 10
3.39. In a period, the non-metallic character increases from left to right. Thus, among B, C, N and F, non-metallic character decreases in the order: F > N > C > B. However, within a group, non-metallic character decreases from top to bottom. Thus, C is more non-metallic than Si. Therefore, the correct sequence of decreasing non-metallic character is: F > N > C > B > Si, i.e., option (c) is correct.
New answer posted
6 months agoContributor-Level 10
(i) An aldehyde with molar mass of 44 u is ethanal, CH3CH=0
(ii) Write two moles of ethanal side by side with their oxygen atoms pointing towards each other.


New answer posted
6 months agoContributor-Level 10
3.38. In a period, metallic character decreases as we move from left to right. Therefore, metallic character of K, Mg and Al decreases in the order: K > Mg > Al. However, within a group, the metallic character, increases from top to bottom. Thus, Al is more metallic than B. Therefore, the correct sequence of decreasing metallic character is: K > Mg > Al > B, i.e., option (d) is correct
New answer posted
6 months agoContributor-Level 10
Step 1. Write the structure of the products side by side with their oxygen atoms pointing towards each other.


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6 months agoTaking an Exam? Selecting a College?
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