Class 11th

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New answer posted

8 months ago

0 Follower 112 Views

V
Vishal Baghel

Contributor-Level 10

A ( g ) ? 2 B ( g ) .

E m 2 m o l V l 4 m o l V l

N e w E q m 4 x V 4 + 2 x V

V * 2 4 x 2 V 4 2 x 2 V

New Eqm 4 x y 2 V 4 + 2 x + 2 y 2 V

= 4 Z 2 V = 4 + 2 Z 2 V ( Z = x + y )

Now, KC =  [ B ] 2 [ A ] = constant

o r , ( 4 V ) 2 ( 2 V ) = ( 4 + 2 Z 2 V ) ( 4 Z 2 V ) Z = 1 . 2 9

 mole of B at new Eqm = 4 + 2Z = 6.58

New answer posted

8 months ago

0 Follower 34 Views

V
Vishal Baghel

Contributor-Level 10

Z = P V m R T 0 . 5 = 2 4 * V m 2 4

V m = 0 . 5 l / m o l e

( P + a V m 2 ) ( V m b ) = R T

( 2 4 + a 0 . 5 2 ) ( 0 . 5 0 . 1 ) = 2 4

2 4 + a 0 . 5 2 = 6 0

a 0 . 5 2 = 3 6

a = 3 6 * 0 . 5 2 = 9 a t m l 2 m o l 2
 

New answer posted

8 months ago

0 Follower 11 Views

V
Vishal Baghel

Contributor-Level 10

The blue color of the solution is due to the ammoniated electron which absorbs energy in infrared region of light

New answer posted

8 months ago

0 Follower 14 Views

V
Vishal Baghel

Contributor-Level 10

Kindly go through the answer

30

New answer posted

8 months ago

0 Follower 126 Views

V
Vishal Baghel

Contributor-Level 10

0 2 = v 2 2 μ k g S r e l

9 2 * 2 = S r e l = 2 . 2 5 m

New answer posted

8 months ago

0 Follower 61 Views

V
Vishal Baghel

Contributor-Level 10

400 * 1 * 12.5 = 500 * 5 * (100 – 36.5)

S = 1 0 6 3 . 5 c a l / g m ° C        

1 g m = 1 6 3 . 5 m o l  

S = 10 cal/mol °C

New answer posted

8 months ago

0 Follower 6 Views

S
Samridhi Mishra

Contributor-Level 10

The authorities have provided the weigtage for COMEDK UGET syllabus for classes 11th and 12th. The topics from class 11th hold 33% while class 12th topics have 67% weightage in the entire question paper, across the 3 subjects.

New answer posted

8 months ago

0 Follower 54 Views

V
Vishal Baghel

Contributor-Level 10

R = u x * T

= g h * 0 . 5 g h * 2 g = h

A B = h + h = 2 h

New answer posted

8 months ago

0 Follower 54 Views

V
Vishal Baghel

Contributor-Level 10

v = ω k = 5 π * 3 0 π = 1 5 0 = T 1 1 0 0

T = 2 2 5 0 0 0 0 1 0 0 = 2 2 5 N

New answer posted

8 months ago

0 Follower 33 Views

V
Vishal Baghel

Contributor-Level 10

v = 2 9 r 2 g ( ρ σ ) η

v ' = 2 9 r 2 g ( ρ 2 σ ) η

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