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Class 11th

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Class 11th Physics

The diagram showing the variation of gravitational potential of earth with distance from the centre of earth is

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Raj Pandey

Contributor-Level 9

$V_{in} = \frac{- G M}{2 R} [3 - {(\frac{r}{R})}^{2}],$

$V_{s u r f a c e} = \frac{- G M}{R}, V_{out} = \frac{- G M}{r}$

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Class 11th Physics

A 20 kg block B is suspended from a cord attached to a 40 kg cart A. Find the ratio of the acceleration of block in cases (i) and (ii) shown in the figure immediately after the system is released from rest. (Neglect friction)

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Raj Pandey

Contributor-Level 9

Case I:

$T - N = 40 a$

and $20 g - T = 20 a$

Also $N = 20 a$

After simplifying, we get

$a = \frac{g}{4}$

Acceleration of block $B, = \sqrt[]{2} a = \frac{g}{2 \sqrt[]{2}} .$

Case II:

$T = 40 a$

and $20 g - T = 20 a$

After simplifying above equation, we get

$a = g / 3$

Ratio $= \frac{g / 2 \sqrt[]{2}}{g / 3} = \frac{3}{2 \sqrt[]{2}} .$

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Class 11th Thermodynamics

The only INCORRECT information is

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Vishal Baghel

Contributor-Level 10

q = 0, w = 0, U = 0 = f (V, T)

As volume changes, temperature must change to maintain constant internal energy.

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Class 11th Chemistry

If Q is a colourless gas with rotten fish smell then select CORRECT statement.

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Vishal Baghel

Contributor-Level 10

Zero acidic hydrogen present in anionic part of (R)

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Class 11th Equilibrium

An equilibrium mixture contains 2.0 moles of A(g) and 4.0 moles of B(g). Now, 2.0 moles of A(g) is added in this equilibrium mixture and the system is allowed to re-achieve equilibrium at constant volume and temperature. Now, the volume of system is doubled at constant temperature. What should be the moles of B(g) at new equilibrium? The reaction involved is

$A (g) \overset{}{?} 2 B (g)$ .

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Vishal Baghel

Contributor-Level 10

$A (g) ? 2 B (g) .$

$E_{m} \frac{2 m o l}{V l} \frac{4 m o l}{V l}$

$N e w {E_{q}}^{m} \frac{4 - x}{V} \frac{4 + 2 x}{V}$

$V * 2 \frac{4 - x}{2 V} \frac{4 - 2 x}{2 V}$

New Eqm $\frac{4 - x - y}{2 V} \frac{4 + 2 x + 2 y}{2 V}$

= $\frac{4 - Z}{2 V} = \frac{4 + 2 Z}{2 V} (Z = x + y)$

Now, KC = $\frac{^{}}{}$ $\frac{{[B]}^{2}}{[A]} =$ constant

$o r, \frac{{(\frac{4}{V})}^{2}}{(\frac{2}{V})} = \frac{(\frac{4 + 2 Z}{2 V})}{(\frac{4 - Z}{2 V})} \Rightarrow Z = 1.29$

mole of B at new Eqm = 4 + 2Z = 6.58

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Class 11th Structure of Atom

A sample of hydrogen atoms de-excites from 6th excited state to the ground state in one or more electronic transitions. If no spectral line is obtained in the Paschen and Brackett series, then the maximum number of spectral lines of different photon energies obtained will be-

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Class 11th Chemistry

The compressibility factor of a Vanderwaal gas is 0.5 at $27 ° C$ and 24 atm. The value of Vanderwaal constant 'a' (in atm-L²/mol²) is (b = 0.10 L/mol, R = 0.08 L-atm/K-mol)

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Vishal Baghel

Contributor-Level 10

^{$Z = \frac{P V_{m}}{R T} \Rightarrow 0.5 = \frac{24 * V_{m}}{24}$}

^{$V_{m} = 0.5 l / m o l e$}

^{$(P + \frac{a}{V_{m}^{2}}) (V_{m} - b) = R T$}

^{$(24 + \frac{a}{0 . 5^{2}}) (0.5 - 0.1) = 24$}

^{$24 + \frac{a}{0 . 5^{2}} = 60$}

^{$\frac{a}{0 . 5^{2}} = 36$}

^{$a = 36 * 0 . 5^{2} = 9 \frac{a t m - l^{2}}{m o l^{2}}$}

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Class 11th Chemistry

Consider the following reactions of 1A metals.

M + $(x + y) N H_{3}$ $\overset{}{\to} {[M {(N H_{3})}_{x}]}^{+} + {[e {(N H_{3})}_{y}]}^{-}$

$M_{(a m)}^{+} + e^{-} + N H_{3} (l) \overset{}{\to} M N H_{2 (a m)} + \frac{1}{2} H_{2} (g)$

Which of the following statement is

INCORRECT?

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Vishal Baghel

Contributor-Level 10

The blue color of the solution is due to the ammoniated electron which absorbs energy in infrared region of light

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Class 11th Chemistry Chemical Bonding and Molecular Structure

Which of the following set contains specie that have interaction energy proportional to $\frac{1}{r^{3}} ?$

(r -> internuclear distance)

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Class 11th Chemistry Hydrocarbon

The oxidation of toluene with hot KMnO₄ gives-

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