Class 11th

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New answer posted

6 months ago

0 Follower 33 Views

V
Vishal Baghel

Contributor-Level 10

Z = P V m R T 0 . 5 = 2 4 * V m 2 4

V m = 0 . 5 l / m o l e

( P + a V m 2 ) ( V m b ) = R T

( 2 4 + a 0 . 5 2 ) ( 0 . 5 0 . 1 ) = 2 4

2 4 + a 0 . 5 2 = 6 0

a 0 . 5 2 = 3 6

a = 3 6 * 0 . 5 2 = 9 a t m l 2 m o l 2
 

New answer posted

6 months ago

0 Follower 10 Views

V
Vishal Baghel

Contributor-Level 10

The blue color of the solution is due to the ammoniated electron which absorbs energy in infrared region of light

New answer posted

6 months ago

0 Follower 13 Views

V
Vishal Baghel

Contributor-Level 10

Kindly go through the answer

30

New answer posted

6 months ago

0 Follower 120 Views

V
Vishal Baghel

Contributor-Level 10

0 2 = v 2 2 μ k g S r e l

9 2 * 2 = S r e l = 2 . 2 5 m

New answer posted

6 months ago

0 Follower 60 Views

V
Vishal Baghel

Contributor-Level 10

400 * 1 * 12.5 = 500 * 5 * (100 – 36.5)

S = 1 0 6 3 . 5 c a l / g m ° C        

1 g m = 1 6 3 . 5 m o l  

S = 10 cal/mol °C

New answer posted

6 months ago

0 Follower 5 Views

S
Samridhi Mishra

Contributor-Level 10

The authorities have provided the weigtage for COMEDK UGET syllabus for classes 11th and 12th. The topics from class 11th hold 33% while class 12th topics have 67% weightage in the entire question paper, across the 3 subjects.

New answer posted

6 months ago

0 Follower 50 Views

V
Vishal Baghel

Contributor-Level 10

R = u x * T

= g h * 0 . 5 g h * 2 g = h

A B = h + h = 2 h

New answer posted

6 months ago

0 Follower 52 Views

V
Vishal Baghel

Contributor-Level 10

v = ω k = 5 π * 3 0 π = 1 5 0 = T 1 1 0 0

T = 2 2 5 0 0 0 0 1 0 0 = 2 2 5 N

New answer posted

6 months ago

0 Follower 25 Views

V
Vishal Baghel

Contributor-Level 10

v = 2 9 r 2 g ( ρ σ ) η

v ' = 2 9 r 2 g ( ρ 2 σ ) η

New answer posted

6 months ago

0 Follower 41 Views

V
Vishal Baghel

Contributor-Level 10

Field lines are proportional to quantity of charge & they originate at positive charge & terminates at -ve charge or at  

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