Class 11th

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New answer posted

2 months ago

0 Follower 7 Views

V
Vishal Baghel

Contributor-Level 10

400 * 1 * 12.5 = 500 * 5 * (100 – 36.5)

S = 1 0 6 3 . 5 c a l / g m ° C        

1 g m = 1 6 3 . 5 m o l  

S = 10 cal/mol °C

New answer posted

2 months ago

0 Follower 2 Views

S
Samridhi Mishra

Contributor-Level 9

The authorities have provided the weigtage for COMEDK UGET syllabus for classes 11th and 12th. The topics from class 11th hold 33% while class 12th topics have 67% weightage in the entire question paper, across the 3 subjects.

New answer posted

2 months ago

0 Follower 10 Views

V
Vishal Baghel

Contributor-Level 10

R = u x * T

= g h * 0 . 5 g h * 2 g = h

A B = h + h = 2 h

New answer posted

2 months ago

0 Follower 3 Views

V
Vishal Baghel

Contributor-Level 10

v = ω k = 5 π * 3 0 π = 1 5 0 = T 1 1 0 0

T = 2 2 5 0 0 0 0 1 0 0 = 2 2 5 N

New answer posted

2 months ago

0 Follower 2 Views

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Vishal Baghel

Contributor-Level 10

v = 2 9 r 2 g ( ρ σ ) η

v ' = 2 9 r 2 g ( ρ 2 σ ) η

New answer posted

2 months ago

0 Follower 14 Views

V
Vishal Baghel

Contributor-Level 10

Field lines are proportional to quantity of charge & they originate at positive charge & terminates at -ve charge or at  

New answer posted

2 months ago

0 Follower 8 Views

V
Vishal Baghel

Contributor-Level 10

B = m g B 1 = B 2

ρ 1 V 1 g = B = ρ w v L D g

ρ 2 ρ W = f 2

ρ 1 > ρ 1

New answer posted

2 months ago

0 Follower 7 Views

V
Vishal Baghel

Contributor-Level 10

λ = v 2 π d 2 n N a = R T 2 π d 2 p N a

= 2 5 3 * 3 0 0 2 * π * 1 0 2 0 * 1 0 5 * 6 * 1 0 2 3

x 3 = v n N a

= ( 2 5 3 * 3 0 0 1 0 5 * 6 * 1 0 2 3 ) 1 / 3

New answer posted

2 months ago

0 Follower 8 Views

V
Vishal Baghel

Contributor-Level 10

d H d t = 2 π x 2 k d T d x

d H d t = 2 π * k * 4 5 1 2 . 5 1 3 = 2 . 2 5 π k W

New answer posted

2 months ago

0 Follower 7 Views

V
Vishal Baghel

Contributor-Level 10

T = 2 π l g

In summer, length will increase due to expansion, hence for same time period we have to decrease l  in summer.

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