Class 11th

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New answer posted

2 months ago

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V
Vishal Baghel

Contributor-Level 10

3 2 x 2 1 x 0 p u t 2 x = t

3 t 2 t 0 t 2 3 t + 2 0

( t 1 ) ( t 2 ) 0 t [ 1 , 2 ]

New answer posted

2 months ago

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V
Vishal Baghel

Contributor-Level 10

T r + 1 = 1 5 C r ( x 2 ) 1 5 r ( 3 λ x ) r

T r + 1 = 1 5 C 4 ( 3 λ ) r . x 3 0 3 r

30 – 3r = 21 => r = 3

λ 3 = 8 2 7 λ = 2 3

New answer posted

2 months ago

0 Follower 3 Views

V
Vishal Baghel

Contributor-Level 10

Kindly go through the answers

(1.25)

New answer posted

2 months ago

0 Follower 7 Views

V
Vishal Baghel

Contributor-Level 10

Kindly go through the answers

(1.75)

New answer posted

2 months ago

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V
Vishal Baghel

Contributor-Level 10

Moles of NO =   6 0 0 * 1 0 3 * 1 0 0 3 0 = 2

moles of NO2 = 2

3NO2 + H2O -> 2HNO3 + NO

0 . 2 M 0 . 4 3 M o r p H = l o g 0 . 4 3 = 0 . 8 8        

New answer posted

2 months ago

0 Follower 3 Views

V
Vishal Baghel

Contributor-Level 10

Kindly go through the answers

(7.00)

New answer posted

2 months ago

0 Follower 3 Views

V
Vishal Baghel

Contributor-Level 10

Kindly go through the answers

(13.00)

New answer posted

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R
Raj Pandey

Contributor-Level 9

When Two rods are connected in series

Q=A (T1T2)td1K1+d2K1=A (T1T2)t (d1+d2)/K

d 1 + d 2 K = d 1 K 1 + d 2 K 2

K= (d1+d2)d1K1+d2K1

New answer posted

2 months ago

0 Follower 3 Views

R
Raj Pandey

Contributor-Level 9

V in = G M 2 R [ 3 ( r R ) 2 ] ,

V s u r f a c e = G M R , V out = G M r

New answer posted

2 months ago

0 Follower 16 Views

R
Raj Pandey

Contributor-Level 9

Case I:

T N = 4 0 a

and 20gT=20a  

Also N = 2 0 a  

After simplifying, we get

a = g 4

Acceleration of block B,=2a=g22.

Case II:

T = 4 0 a

and 20gT=20a

After simplifying above equation, we get

a = g / 3

Ratio = g / 2 2 g / 3 = 3 2 2 .

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