Class 12th

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New answer posted

9 months ago

0 Follower 8 Views

R
Raj Pandey

Contributor-Level 9

E = K p r 3 1 + 3 c o s 2 ? θ

E 1 r 3

New answer posted

9 months ago

0 Follower 2 Views

R
Raj Pandey

Contributor-Level 9

i m a x = E m a x R = N B A ω R

i m a x = 1000 * 2 * 10 - 5 * π 10 2 * 2 12.56

i m a x = 1 A

New answer posted

9 months ago

0 Follower 4 Views

R
Raj Pandey

Contributor-Level 9

Area = Length *  Breadth

= 55.3 * 25

= 1382.5

= 14 * 10 2

New answer posted

9 months ago

0 Follower 8 Views

R
Raj Pandey

Contributor-Level 9

λ = h p

Graph will be hyperbolic

 

New answer posted

9 months ago

0 Follower 25 Views

A
alok kumar singh

Contributor-Level 10

V P = V q + V - q

= K q 5 - 3 + K ( - q ) 5 + 3 * 10 2 = K q 2 - K q 8 * 10 2 = 3 K q 8 * 10 2

New answer posted

9 months ago

0 Follower 3 Views

A
alok kumar singh

Contributor-Level 10

R = R 0 ( 1 + α Δ T )

6.8 = 2 [ 1 + α * ( 80 - 0 ) ] α = 3.4 - 1 80 = 0.03 = 3 * 10 - 2 ? C - 1

New answer posted

9 months ago

0 Follower 7 Views

A
alok kumar singh

Contributor-Level 10

B ? P = B ? upper wire   + B ? semi-circle   ? + B ? lower-wire  

B P = - μ 0 i 4 π R + μ 0 i 4 R - μ 0 i 4 π R = μ 0 i 4 R 1 - 2 π  pointing away from the page

New answer posted

9 months ago

0 Follower 14 Views

A
alok kumar singh

Contributor-Level 10

Time period of satellite

T = 2 π R 3 G M

= 2 π R 3 G d 4 3 π R 3

T = 3 π G d 3 π G d = T 2

New answer posted

9 months ago

0 Follower 4 Views

R
Raj Pandey

Contributor-Level 9

B = μ 0 n i = μ 0 N l i

B = 4 π * 10 - 7 * 100 10 - 3 * 1 = 12.56 * 10 - 2 T

New answer posted

9 months ago

0 Follower 3 Views

R
Raj Pandey

Contributor-Level 9

P = 1 f = ( μ - 1 ) 1 R 1 - 1 R 2

P = 3 2 - 1 1 0.2 + 1 0.2

P = 1 2 2 0.2 = 10 2 = + 5 D

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