Class 12th

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New answer posted

7 months ago

0 Follower 3 Views

A
alok kumar singh

Contributor-Level 10

By conservation of angular momentum, I? ω? + I? ω? = (I? +I? )ω
ω = (I? ω? +I? ω? )/ (I? +I? ) = (0.110 + 0.25)/ (0.1+0.2) = 2/0.3 = 20/3 rad/s
K = ½ (I? +I? )ω² = ½ (0.3) (20/3)² = 20/3 J.

New answer posted

7 months ago

0 Follower 9 Views

A
alok kumar singh

Contributor-Level 10

m = I (abk + abj)
|m| = Iab√2
Direction ⇒ (j+k)/√2

New answer posted

7 months ago

0 Follower 14 Views

A
alok kumar singh

Contributor-Level 10

R = 100Ω. tanφ = (X_L-X_C)/R. tan45° = X_L/R (since it's an inductor). X_L=R=100Ω.
Lω=100 ⇒ L (2πf)=100 ⇒ L = 100/ (2π1000) ≈ 1.59 * 10? ² H. The closest option is (A).

New answer posted

7 months ago

0 Follower 4 Views

A
alok kumar singh

Contributor-Level 10

l = 10 * pitch = 10 * (2πmvcosθ/qB)
= 20π * 1.67*10? ²? * 4*10? * (1/2) / (1.6*10? ¹? * 0.3) = 0.44 m

New answer posted

7 months ago

0 Follower 30 Views

A
alok kumar singh

Contributor-Level 10

Δl = lαΔT ⇒ Δl/l = αΔT = 0.02%
Δρ = -ργΔT
|Δρ/ρ| = γΔT = 3αΔT = 3 (0.02%) = 0.06%

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