Tags Class 12th

Class 12th

Get insights from 12k questions on Class 12th, answered by students, alumni, and experts. You may also ask and answer any question you like about Class 12th

Follow Ask Question

12k

Questions

Discussions

Active Users

Followers

New answer posted

4 months ago

Class 12th Differential Equations

Let y = y(x) be the solution of the differential equation cosx(dy/dx) + 2ysinx = sin2x, x ∈ (0, π/2). If y(π/3) = 0, then y(π/4) is equal to:

0 Follower 12 Views

Vishal Baghel

Contributor-Level 10

dy/dx + 2tanx · y = 2sinx
I.F. = e^ (∫2tanxdx) = sec²x
Solution is y·sec²x = ∫2sinx·sec²xdx + C
ysec²x = 2secx + C
0 = 2·2 + c ⇒ c = -4
ysec²x = 2secx - 4
y (π/4) = √2 - 2

0 0

New answer posted

4 months ago

Class 12th Maths

If for some α ∈ R, the lines L₁: (x+1)/2 = (y-2)/(-1) = (z-1)/1 and L₂: (x+2)/α = (y+1)/(5-α) = (z+1)/1 are coplanar, then the line L₂ passes through the point:

0 Follower 5 Views

Vishal Baghel

Contributor-Level 10

Line are coplanar
so | [α, 5-α, 1], [2, -1, 1], | = 0
−5α + (α – 5)3 + 7 = 0
-2α = 8 ⇒ α = −4
⇒ L? : (x+2)/-4 = (y+1)/9 = (z+1)/1
Now by cross checking option (A) is correct.

0 0

New answer posted

4 months ago

Class 12th Determinants

If the system of linear equations
x + y + 3z = 0
x + 3y + k²z = 0
3x + y + 3z = 0
has a non-zero solution (x, y, z) for some k ∈ R, then x + (k/y)z is equal to:

0 Follower 3 Views

Vishal Baghel

Contributor-Level 10

So D = 0 → |, [1,3, k²], | = 0 ⇒ k² = 9
x + y + 3z = 0
x + 3y + 9z = 0
3x + y + 3z = 0
(1)- (3)
x = 0 ⇒ y + 3z = 0
y/z = -3
So x + (y/z) = -3

0 0

New answer posted

4 months ago

Class 12th Maths

The shortest distance between the lines $\frac{x - 3}{3} = \frac{y - 8}{- 1} = \frac{z - 3}{1}$ $\frac{}{} \frac{}{} \frac{}{}$ and $\frac{x + 3}{- 3} = \frac{y + 7}{2} = \frac{z - 6}{4}$ $\frac{}{} \frac{}{} \frac{}{}$ is:

0 Follower 6 Views

Raj Pandey

Contributor-Level 9

w = I + j - 3k
p = 3i - j + k
q = -3i + 2j + 4k
p * q = |i, j, k; 3, -1, 1; -3, 2, 4| = -6i - 15j + 3k
S.D. = |AD. (p * q)|/|p * q| = | (36+225+9)|/√ (36+225+9) = 3√30

0 0

New answer posted

4 months ago

Class 12th Redox Reactions

The volume, in mL, of 0.02M K₂Cr₂O₇ solution required to react with 0.288 g of ferrous oxalate in acidic medium is (Molar mass of Fe = 56 mol⁻¹)

0 Follower 20 Views

Vishal Baghel

Contributor-Level 10

50.00
K? Cr? O? + FeC? O? → Fe³? + CO? + Cr³? + K? + H? O
n_f=6 n_f=3
Now apply equivalent concept
0.02 * 6 * V = (0.288 / (144/3) * 10³
Normality
V = (0.288 * 10³)/ (48 * 6 * 0.02) = 50.00 mL

0 0

New answer posted

4 months ago

Class 12th Coordination Compounds

Considering that ∆₀ > P, the magnetic moment (in BM) of [Ru(H₂O)₆]²⁺ would be

0 Follower 3 Views