Class 12th

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New answer posted

10 months ago

0 Follower 2 Views

V
Vishal Baghel

Contributor-Level 10

λ=h/p, p=√2mk. λ∝1/√m

New answer posted

10 months ago

0 Follower 4 Views

A
alok kumar singh

Contributor-Level 10

(ap-b)²+ (bp-c)²+ (cp-d)²=0 ⇒ p=b/a=c/b=d/c. a, b, c, d are in G.P.

New answer posted

10 months ago

0 Follower 2 Views

A
alok kumar singh

Contributor-Level 10

p∨ (¬p∧q) = (p∨¬p)∧ (p∨q)=T∧ (p∨q)=p∨q. Negation is ¬p∧¬q.

New answer posted

10 months ago

0 Follower 7 Views

A
alok kumar singh

Contributor-Level 10

(80+1)? /8 = (¹C?80? +.+¹C? )/8. Remainder is 1/8.

New answer posted

10 months ago

0 Follower 3 Views

A
alok kumar singh

Contributor-Level 10

S.D.=√ (Σ (x-a)²/n - (Σ (x-a)/n)²) = √ (a-1).

New answer posted

10 months ago

0 Follower 10 Views

R
Raj Pandey

Contributor-Level 9

The expression inside log is a GP sum: (1/3)/ (1-1/3) = 1/2.
log? (1/2) = 1/2.
The series S = 1+2/3+6/3²+.
S - S/3 = 1 + 4/3² + 4/3³ + . = 1 + (4/9)/ (1-1/3) = 1+2/3=5/3.
(2/3)S = 5/3 ⇒ S=5/2.
l = (5/2)/ (1/2)=5. l²=25.

New answer posted

10 months ago

0 Follower 12 Views

V
Vishal Baghel

Contributor-Level 10

r = mv/qB?
To not collide, r∴ Vmax = qB? d/m
Note: It should be maximum instead of minimum.

New answer posted

10 months ago

0 Follower 4 Views

A
alok kumar singh

Contributor-Level 10

|z|-Re (z)≤1 ⇒ √ (x²+y²)-x≤1 ⇒ √ (x²+y²)≤1+x ⇒ y²≤1+2x=2 (x+1/2).

New answer posted

10 months ago

0 Follower 29 Views

V
Vishal Baghel

Contributor-Level 10

τ = RC = 10µS
For 0

New answer posted

10 months ago

0 Follower 30 Views

R
Raj Pandey

Contributor-Level 9

S = {n ∈ N | [n i; 0 1] [a b; c d] = [a b; c d] ∀a, b, c, d ∈ R}
[na+ic, nb+id; c, d] = [a, b;c, d]
This must be an identity matrix. n=1. The question seems to have typos. Let's follow the solution logic.
The solution implies the matrix must be [1 0; 0 1] or [-1 0; 0 -1]. And n must be a multiple of 8.
2-digit multiples of 8 are 16, 24, ., 96. Total 11 numbers.

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