Class 12th

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New answer posted

4 months ago

0 Follower 6 Views

V
Vishal Baghel

Contributor-Level 10

Potential of centre, = V =
Vc = K (Σq)/R
Vc = K (0)/R = 0
Electric field at centre E_B = E_B = ΣE
Let E be electric field produced by each

charge at the centre, then resultant electric field will be
Ec = 0, since equal electric field vectors are acting at equal angle so their resultant is equal to zero.

New answer posted

4 months ago

0 Follower 4 Views

V
Vishal Baghel

Contributor-Level 10

Energies of given Radiation can have
The following relation
Eγ-Rays > EX-Rays > Emicrowave > EAM Radiowaves
∴ λγ-Rays < X-Rays < microwave < AM Radiowaves
According to tres.
(a) Microwave → 10? ³ m
(b) Gamma Rays → 10? ¹? m (ii)
(c) AM Radio wve → 100 m (i)
(d) X-Rays → 10? ¹? m

New answer posted

4 months ago

0 Follower 4 Views

V
Vishal Baghel

Contributor-Level 10

M = µ? NiA
Here
µ? = Relative permeability
N = Number of turns
i = Current
A = Area of cross section
M = µ? NiA = µ? nliA
M = µ? niV = 1000 (1000) (0.5) (10? ³) = 500 = 5 * 10²Am²

New answer posted

4 months ago

0 Follower 9 Views

V
Vishal Baghel

Contributor-Level 10

Now, using junction analysis
We can say, q? + q? + q? = 0
2 (x - 6) + 4 (x - 6) + 5 (x) = 0
x = 36/11, q? = 36 (5)/11 = 180/11
q? = 16.36µC

New answer posted

4 months ago

0 Follower 4 Views

R
Raj Pandey

Contributor-Level 9

Without catalyst: K = A e - E a / R T

  Presence catalyst:   10 6 K = A e - E c / R T E q ( B ) - E q ( A ) 10 6 = e - ( E - E c ) / R T E - E c R T = 2.303 * 6 Δ E = E c - E = ( - 2.303 ) * 6 R T

New answer posted

4 months ago

0 Follower 11 Views

R
Raj Pandey

Contributor-Level 9

Kindly consider the following Image

 

New answer posted

4 months ago

0 Follower 24 Views

V
Vishal Baghel

Contributor-Level 10

Initially S? L = 2m


S? L = √2² + (3/2)²
S? L = 5/2 = 2.5 m
? x = S? L - S? L = 0.5 m
So since λ = 1 m. ∴? x = λ/2
So white listener moves away from S? Then? x (= S? L − S? L) increases and hence, at? x = λ first maxima will appear.? x = λ = S? L − S? L.
1 = d - 2 ⇒ d = 3 m.

New answer posted

4 months ago

0 Follower 3 Views

R
Raj Pandey

Contributor-Level 9

Diborane B 2 H 6  is used to reduced carboxylic acid to alcohol.

New answer posted

4 months ago

0 Follower 2 Views

R
Raj Pandey

Contributor-Level 9

According to Hardy-Schulze Rule coagulation value α 1   Coagulation Power  

New answer posted

4 months ago

0 Follower 7 Views

A
alok kumar singh

Contributor-Level 10

= 128 3

3 + 2 ( a ? b ? + b ? c ? + c ? a ? ) = 0

a ? b ? + b ? c ? + c ? a ? = - 3 2 d ? = a ? * b ? + b ? * c ? + c ? * a ? d ? = 3 ( a ? * b ? )

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