Class 12th
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10 months agoContributor-Level 10
(ap-b)²+ (bp-c)²+ (cp-d)²=0 ⇒ p=b/a=c/b=d/c. a, b, c, d are in G.P.
New answer posted
10 months agoNew answer posted
10 months agoContributor-Level 9
The expression inside log is a GP sum: (1/3)/ (1-1/3) = 1/2.
log? (1/2) = 1/2.
The series S = 1+2/3+6/3²+.
S - S/3 = 1 + 4/3² + 4/3³ + . = 1 + (4/9)/ (1-1/3) = 1+2/3=5/3.
(2/3)S = 5/3 ⇒ S=5/2.
l = (5/2)/ (1/2)=5. l²=25.
New answer posted
10 months agoContributor-Level 10
r = mv/qB?
To not collide, r
Note: It should be maximum instead of minimum.
New answer posted
10 months agoContributor-Level 10
|z|-Re (z)≤1 ⇒ √ (x²+y²)-x≤1 ⇒ √ (x²+y²)≤1+x ⇒ y²≤1+2x=2 (x+1/2).
New answer posted
10 months agoContributor-Level 9
S = {n ∈ N | [n i; 0 1] [a b; c d] = [a b; c d] ∀a, b, c, d ∈ R}
[na+ic, nb+id; c, d] = [a, b;c, d]
This must be an identity matrix. n=1. The question seems to have typos. Let's follow the solution logic.
The solution implies the matrix must be [1 0; 0 1] or [-1 0; 0 -1]. And n must be a multiple of 8.
2-digit multiples of 8 are 16, 24, ., 96. Total 11 numbers.
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