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Class 12th English

Answer the questions on the basis of the information given below.

The regular mathematics faculty could not teach because of being sick. As a stop gap arrangement different visiting faculty taught different topics on 4 different days in a week. The scheduled time for class was 7:00 am with maximum permissible delay of 20 minutes. The monsoon made the city bus schedules erratic and therefore the classes started on different times on different days.

Mr. Singh didn't teach on Thursday. Calculus was taught in the class that started at 7:20 am. Mr. Chatterjee took the class on Wednesday, but he didn't teach probability. The class on Monday

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alok kumar singh

Contributor-Level 10

Professor	Day	Timing	Subject
Mr. Singh	Friday	07:10	Set theory
Mr. Chatterjee	Wednesday	07:20	Calculus
Mr. Dutta	Monday	07:00	Probability
Mr. Banerjee	Thursday	07:05	Ratio and Proportion

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11 months ago

Class 12th Chemistry Coordination Compounds

Calamine and Malachite, respectively, are the ores of:

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alok kumar singh

Contributor-Level 10

Calamine is the ore of zinc i.e. ZnCO₃.

Malachite is the ore of copper i.e. CuCO₃.Cu (OH)₂.

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11 months ago

Class 12th Maths

Let $A = (\begin{matrix} 1 & - 1 & 0 \\ 0 & 1 & - 1 \\ 0 & 0 & 1 \end{matrix}) a n d B = 7 A^{20} - 20 A^{7} + 2 I,$ where I is an identity matrix of order 3 * 3. If B = $[b_{i j}],$ then b₁₃ is equal to……………

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Raj Pandey

Contributor-Level 9

$A = [\begin{matrix} 1 & - 1 & 0 \\ 0 & 1 & - 1 \\ 0 & 0 & 1 \end{matrix}]$

B = 7A20 – 20A7 + 2l

$A^{2} [\begin{matrix} 1 & - 1 & 0 \\ 0 & 1 & - 1 \\ 0 & 0 & 1 \end{matrix}] [\begin{matrix} 1 & - 1 & 0 \\ 0 & 1 & - 1 \\ 0 & 0 & 1 \end{matrix}] = [\begin{matrix} 1 & - 2 & 1 \\ 0 & 1 & - 2 \\ 0 & 0 & 1 \end{matrix}]$

$A^{3} = [\begin{matrix} 1 & - 2 & 1 \\ 0 & 1 & - 2 \\ 0 & 0 & 1 \end{matrix}] [\begin{matrix} 1 & - 1 & 0 \\ 0 & 1 & - 1 \\ 0 & 0 & 1 \end{matrix}] = [\begin{matrix} 1 & - 3 & 3 \\ 0 & 1 & - 3 \\ 0 & 0 & 1 \end{matrix}]$

$A^{4} = [\begin{matrix} 1 & - 3 & 3 \\ 0 & 1 & - 3 \\ 0 & 0 & 1 \end{matrix}] [\begin{matrix} 1 & - 1 & 0 \\ 0 & 1 & - 1 \\ 0 & 0 & 1 \end{matrix}] = [\begin{matrix} 1 & - 4 & 6 \\ 0 & 1 & - 4 \\ 0 & 0 & 1 \end{matrix}]$

$a_{13} o f A, A^{2}, A^{3}, . . . . . . .$

are 0, 1, 3, 6,.

For 0, 1, 3, 6, .

$S_{n} = 0 + 1 + 3 + 6 + . . . . + t_{n}$

$S_{n} = 0 + + 3 + . . . . + t_{n - 1} + t_{n}$

$t_{n} = 1 + 2 + 3 + . . . + (t_{n} - t_{n - 1})$

$= \frac{(n - 1) . n}{2}$

$b_{13} = 7 (190) - 20 (21) + 0$

= 1330 – 420 = 910

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11 months ago

Class 12th Biomolecules

Identify the element for which electronic configuration in +3 oxidation state is [Ar]3d⁵.

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alok kumar singh

Contributor-Level 10

Electronic configuration of Fe is [Ar] 4s²3d⁶ and in +3 oxidation state it has [Ar] 4s⁰3d⁵ configuration.

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11 months ago

Class 12th English

Answer the questions on the basis of the information given below.

Mr. Singh didn't teach on Thursday. Calculus was taught in the class that started at 7:20 am. Mr. Chatterjee took the class on Wednesday, but he didn't teach probability. The class on Monday

...more

0 Follower 2 Views

alok kumar singh

Contributor-Level 10

Professor	Day	Timing	Subject
Mr. Singh	Friday	07:10	Set theory
Mr. Chatterjee	Wednesday	07:20	Calculus
Mr. Dutta	Monday	07:00	Probability
Mr. Banerjee	Thursday	07:05	Ratio and Proportion

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New question posted

11 months ago

Class 12th Maths

Let $A = (\begin{matrix} 1 & - 1 & 0 \\ 0 & 1 & - 1 \\ 0 & 0 & 1 \end{matrix}) a n d B = 7 A^{20} - 20 A^{7} + 2 I,$ where I is an identity matrix of order 3 × 3. If B = $[b_{i j}],$ then b₁₃ is equal to……………

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New question posted

11 months ago

Class 12th Chemistry

The potassium ferrocyanide solution gives a Prussian blue colour, when added to:

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New question posted

11 months ago

Class 12th Atomic Masses and Composition of Nucleus

How does number of neutrons affect the stability of nucleus?

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11 months ago

Class 12th Maths

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New question posted

11 months ago

Class 12th Chemistry

The potassium ferrocyanide solution gives a Prussian blue colour, when added to:

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