Class 12th

Answer the questions on the basis of the information given below.

Four houses Bachan, Khan, Chaudhary and Sharma are located in a row in the given order. Each of the houses is occupied by a person earning a fixed amount of a salary. The four persons are Powell, Kartik, Leo, and Samay.

Rea the following instruction carefully:

I. Powell lives between Samay and Kartik

II. Leo does not stay in Bachan house

III. The person living in Chaudhary house earns more than that of person living in Bachan

IV. Salary of Samay is more than that of Powell but lesser than that of Kartik

V. One of the person earns Rs. 80000

VI. The person earning Rs. 1100

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Contributor-Level 10

Name	Blue	Green	Red	Yellow	Salary
Paul	*	?	*	*	30
Krishna	*	*	?	*	110
Laxman	*	*	*	?	50
Som	?	*	*	*	80

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5 months ago

Class 12th Chemistry

Identify A in the following reaction

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Class 12th Atomic Masses and Composition of Nucleus

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How does the number of neutrons affect the stability of a nucleus?

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Jaya Sharma

Contributor-Level 10

The number of neutrons in nucleus has an important role in determining the stability of nucleus. Stability of nucleus is affected by the balance between number of protons and neutrons and the number of nucleons. In lighter elements, the most stable nuclei has roughly equal number of protons and neutrons. For instance, Carbon-12 is the most common isotope of carbon with 6 protons and 6 neutrons.

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cas C,ad v,mad v,aDcA

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Answer the questions on the basis of the information given below.

The regular mathematics faculty could not teach because of being sick. As a stop gap arrangement different visiting faculty taught different topics on 4 different days in a week. The scheduled time for class was 7:00 am with maximum permissible delay of 20 minutes. The monsoon made the city bus schedules erratic and therefore the classes started on different times on different days.

Mr. Singh didn’t teach on Thursday. Calculus was taught in the class that started at 7:20 am. Mr. Chatterjee took the class on Wednesday, but he didn’t teach probability. The clas

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5 months ago

Answer the questions on the basis of the information given below.

Mr. Singh didn't teach on Thursday. Calculus was taught in the class that started at 7:20 am. Mr. Chatterjee took the class on Wednesday, but he didn't teach probability. The class on Monday

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Class 12th Chemistry Coordination Compounds

Contributor-Level 10

Professor	Day	Timing	Subject
Mr. Singh	Friday	07:10	Set theory
Mr. Chatterjee	Wednesday	07:20	Calculus
Mr. Dutta	Monday	07:00	Probability
Mr. Banerjee	Thursday	07:05	Ratio and Proportion

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Calamine and Malachite, respectively, are the ores of:

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Contributor-Level 10

Calamine is the ore of zinc i.e. ZnCO₃.

Malachite is the ore of copper i.e. CuCO₃.Cu (OH)₂.

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Class 12th Maths

Let $A = (\begin{matrix} 1 & - 1 & 0 \\ 0 & 1 & - 1 \\ 0 & 0 & 1 \end{matrix}) a n d B = 7 A^{20} - 20 A^{7} + 2 I,$ where I is an identity matrix of order 3 * 3. If B = $[b_{i j}],$ then b₁₃ is equal to……………

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Raj Pandey

Contributor-Level 9

$A = [\begin{matrix} 1 & - 1 & 0 \\ 0 & 1 & - 1 \\ 0 & 0 & 1 \end{matrix}]$

B = 7A20 – 20A7 + 2l

$A^{2} [\begin{matrix} 1 & - 1 & 0 \\ 0 & 1 & - 1 \\ 0 & 0 & 1 \end{matrix}] [\begin{matrix} 1 & - 1 & 0 \\ 0 & 1 & - 1 \\ 0 & 0 & 1 \end{matrix}] = [\begin{matrix} 1 & - 2 & 1 \\ 0 & 1 & - 2 \\ 0 & 0 & 1 \end{matrix}]$

$A^{3} = [\begin{matrix} 1 & - 2 & 1 \\ 0 & 1 & - 2 \\ 0 & 0 & 1 \end{matrix}] [\begin{matrix} 1 & - 1 & 0 \\ 0 & 1 & - 1 \\ 0 & 0 & 1 \end{matrix}] = [\begin{matrix} 1 & - 3 & 3 \\ 0 & 1 & - 3 \\ 0 & 0 & 1 \end{matrix}]$

$A^{4} = [\begin{matrix} 1 & - 3 & 3 \\ 0 & 1 & - 3 \\ 0 & 0 & 1 \end{matrix}] [\begin{matrix} 1 & - 1 & 0 \\ 0 & 1 & - 1 \\ 0 & 0 & 1 \end{matrix}] = [\begin{matrix} 1 & - 4 & 6 \\ 0 & 1 & - 4 \\ 0 & 0 & 1 \end{matrix}]$

$a_{13} o f A, A^{2}, A^{3}, . . . . . . .$

are 0, 1, 3, 6,.

For 0, 1, 3, 6, .

$S_{n} = 0 + 1 + 3 + 6 + . . . . + t_{n}$

$S_{n} = 0 + + 3 + . . . . + t_{n - 1} + t_{n}$

$t_{n} = 1 + 2 + 3 + . . . + (t_{n} - t_{n - 1})$

$= \frac{(n - 1) . n}{2}$

$b_{13} = 7 (190) - 20 (21) + 0$

= 1330 – 420 = 910

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Class 12th Biomolecules

Identify the element for which electronic configuration in +3 oxidation state is [Ar]3d⁵.

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Contributor-Level 10

Electronic configuration of Fe is [Ar] 4s²3d⁶ and in +3 oxidation state it has [Ar] 4s⁰3d⁵ configuration.

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Answer the questions on the basis of the information given below.

Mr. Singh didn't teach on Thursday. Calculus was taught in the class that started at 7:20 am. Mr. Chatterjee took the class on Wednesday, but he didn't teach probability. The class on Monday

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