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11 months ago

Class 12th Physics

Two resistors R₁ = $(4 \pm 0.8) Ω a n d R_{2} = (4 \pm 0.4) Ω$ are connected in parallel. The equivalent resistance of their parallel combination will be:

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alok kumar singh

Contributor-Level 10

$\frac{1}{R_{e q}} = \frac{1}{R_{1}} + \frac{1}{R_{2}} = \frac{1}{4} + \frac{1}{4}$

R_eq = 2

$\frac{Δ R_{e q}}{R_{e q}^{2}} = \frac{Δ R_{1}}{R_{1}^{2}} + \frac{Δ R_{2}}{R_{2}^{2}}$

$\begin{array}{l} \frac{Δ R_{e q}}{4} = \frac{0.8}{16} + \frac{0.4}{16} + \frac{1.2}{16} \\ R_{e q} = 0.3 \end{array}$

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New answer posted

11 months ago

Class 12th English

There were ten events in the last years “annual sports meet” of XYZ international school. Following guidelines have been issued to schedule the “annual sports meet”:

I. A school board has organized the meet for ten events Cultural fest, Science exhibition, Writing , Reading, Dress, Quiz , Festivals, Planting, Drawing and Picnic on six days of week with holiday on Sunday; not having more than two events on any of the days.

II. Event begins on Wednesday with event Quiz .

III. Reading is accompanied by some other event but not on Thursday. Cultural fest and Festivals

are on the same day immediately after the holi

...more

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Payal Gupta

Contributor-Level 10

According to the information provided following arrangement of the schedule will be formed.

Days	Events
Wednesday	Quiz and Drawing
Thursday	Dress and Planting
Friday	Reading and science
Saturday	Writing
Sunday	Holiday (*)
Monday	Cultural fest, festival
Tuesday	Picnic

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New answer posted

11 months ago

Class 12th Maths

If 'R' is the least value of 'a' such that the function f(x) = x² + ax + 1 is increasing on [1, 2] and 'S' is the greatest value of 'a' such that the function f(x) = x² + ax + 1 is decreasing on [1, 2], then the value of $| R - S |$ is________.

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Raj Pandey

Contributor-Level 9

$f (x) = x^{2} + a x + 1 \Rightarrow f' (x) = 2 x + a$

for increasing $f' (x) \geq 0$

$∴ 2 x + a \geq 0 \Rightarrow a \geq - 2 x \Rightarrow a \geq - 2 * 2 \Rightarrow a \geq - 4 ∴ R = - 4$

And for decreasing $f' (x) \leq 0 \Rightarrow a \leq - 2 x \Rightarrow a \leq - 2 * 1 ∴ S = - 2$

|R – S| = 2

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New answer posted

11 months ago

Class 12th English

Directions for questions: Read the information carefully and answer the questions given below.

There were ten events in the last years “annual sports meet” of XYZ international school. Following guidelines have been issued to schedule the “annual sports meet”:

II. Event begins on Wednesday with event Quiz .

III. Reading is accompanied by some other event

...more

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Payal Gupta

Contributor-Level 10

According to the information provided following arrangement of the schedule will be formed.

Days	Events
Wednesday	Quiz and Drawing
Thursday	Dress and Planting
Friday	Reading and science
Saturday	Writing
Sunday	Holiday (*)
Monday	Cultural fest, festival
Tuesday	Picnic

0 0

New answer posted

11 months ago

Class 12th English

Some children were taking free throws at the basketball court in school during lunch break. Below are some facts about how many baskets these children shot.

I. Giana shot 8 baskets less than Amlia.

II. Drew and Raddix together shot 37 baskets.

III. Joanna shot 8 baskets more than Drew.

IV. Amlia shot 5 baskets more than Drew.

V. Amlia and Giana together shot 40 baskets.

How many shots were thrown by Drew?

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Payal Gupta

Contributor-Level 10

According to given condition, we conclude:

I. Amlia – Giana = 8

II. Drew + Raddix = 37

III. Joanna = Drew + 8

IV. Amlia = Drew + 5

V. Amlia + Giana = 40

Using (I) and (IV),

Amlia = 24, Giana = 16

Using (IV),

Drew = 19

Using (III),

Joanna = 27

Using (II),

Raddix = 18

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New answer posted

11 months ago

Class 12th English

Some children were taking free throws at the basketball court in school during lunch break. Below are some facts about how many baskets these children shot.

I. Giana shot 8 baskets less than Amlia.

II. Drew and Raddix together shot 37 baskets.

III. Joanna shot 8 baskets more than Drew.

IV. Amlia shot 5 baskets more than Drew.

V. Amlia and Giana together shot 40 baskets.

Which of the following statements is false?

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Payal Gupta

Contributor-Level 10

According to given condition, we conclude:

I. Amlia – Giana = 8

II. Drew + Raddix = 37

III. Joanna = Drew + 8

IV. Amlia = Drew + 5

V. Amlia + Giana = 40

Using (I) and (IV),

Amlia = 24, Giana = 16

Using (IV),

Drew = 19

Using (III),

Joanna = 27

Using (II),

Raddix = 18

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New answer posted

11 months ago

Class 12th Ncert Solutions Maths class 12th

If the following system of linear equations

2x + y + z = 5

x – y + z = 3

x + y + az = b

has no solution, then:

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Raj Pandey

Contributor-Level 9

$Δ = | \begin{matrix} 2 & 1 & 1 \\ 1 & - 1 & 1 \\ 1 & 1 & a \end{matrix} | = 2 (- a - 1) + (1 - a) + 2 = - 3 a + 1$

$Δ_{3} = | \begin{matrix} 2 & 1 & 5 \\ 1 & - 1 & 3 \\ 1 & 1 & b \end{matrix} | = 2 (- b - 1) + (3 - b) + 5 * 2 = - 3 b + 7$

For a = $\frac{1}{3}, b \neq \frac{7}{3},$ $\frac{}{} \frac{}{}$ system has no solution

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New answer posted

11 months ago

Class 12th English

Some children were taking free throws at the basketball court in school during lunch break. Below are some facts about how many baskets these children shot.

I. Giana shot 8 baskets less than Amlia.

II. Drew and Raddix together shot 37 baskets.

III. Joanna shot 8 baskets more than Drew.

IV. Amlia shot 5 baskets more than Drew.

V. Amlia and Giana together shot 40 baskets.

Which of the following statements is true?

0 Follower 2 Views

Payal Gupta

Contributor-Level 10

According to given condition, we conclude:

I. Amlia – Giana = 8

II. Drew + Raddix = 37

III. Joanna = Drew + 8

IV. Amlia = Drew + 5

V. Amlia + Giana = 40

Using (I) and (IV),

Amlia = 24, Giana = 16

Using (IV),

Drew = 19

Using (III),

Joanna = 27

Using (II),

Raddix = 18

Drew and Joanna = 19 + 27 = 46

0 0

New answer posted

11 months ago

Class 12th Physics

A cube is placed inside an electric field, The side of the cube is 0.5m and is placed in the field as shown in the given figure. The change inside the cube is:

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alok kumar singh

Contributor-Level 10

Direction of E in the direction of y axes so flux is only due to top and bottom surface for bottom surface y = 0 E = 0

and for top surface y = 0.5 m So

$E = 150 * {(0.5)}^{2} = \frac{150}{4}$

$f l u x f l o w i n g ? = E A = \frac{150}{4} * {(0.5)}^{2}$

$= \frac{150}{16}$

Gausses law $? = \frac{q}{ε_{0}}$

$\frac{150}{16} = \frac{q}{ε_{0}}$

$= 8.3 * 1 0^{- 11} C$

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New answer posted

11 months ago

Class 12th English

Answer the questions on the basis of the information given below.

In a school when a survey is conducted on liking of subjects out of three subjects physics, chemistry mathematics then outcome is as follow.

Total number of students who like physics, chemistry and mathematics is 30, 40, 50 respectively. 10 students shown interest in all three subjects, Number of students who like physics and mathematics both is equal to number of students who like chemistry and mathematics both and is equal to 3/4 times number of students who like physics and chemistry both 15 students like only chemistry.

When class teacher saw this survey report he to

...more

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alok kumar singh

Contributor-Level 10

From the given condition g = 10,

Number of students who like both Physics and Maths = 10 + f

Number of students who like both chemistry and Maths = 10 + e

From given condition 10 + f = 10 + e or e = f

Similarly from 3^rd condition ¾ (10 + e) = 10 + d

Or 30 + 3e = 40 + 4d

Since 15 students like only chemistry hence b = 15

Number of students who like only chemistry is 40

Hence e + g + d + b = 40

or e + 10 + (3e – 10)/4 + 15 = 40

or (7e – 10)/4 = 15 or 7e = 70 or e = 10

Hence a = 5, c = 20, f = e = 10, d = 5

Hence the distribution is as follows

As per the observation of class teacher actual numbers of students who like Physics in

...more

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