Class 12th

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New answer posted

5 months ago

0 Follower 3 Views

A
alok kumar singh

Contributor-Level 10

BOD is biological oxygen demand which represents the amount of oxygen required to degrade organic matter in water.

Higher the BOD more polluted the water is

So; here water sample with BOD = 3 ppm is the cleanest

New answer posted

5 months ago

Answer the questions on the basis of the information given below.

There are five friends P, Q, R, S and T. Two of them play table tennis while the other three play different games, viz. football, cricket and chess. One table tennis player and the chess player stay on the same floor while the other three stay on floors 2, 4 and 5. Two of the players are industrialists while the other three belong to different occupations viz. teaching, medicine and engineering. The chess player is the oldest while one of the table tennis players, who plays at the national level is the youngest. The other table tennis player who plays at the regional lev

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0 Follower 1 View

A
alok kumar singh

Contributor-Level 10

Name

Game

Occupation

Floor

Age

P

Tennis

Industrialist

3

the youngest (1)

Q

Chess

Engineer

3

the oldest (5)

R

Football

 

 

6

S

Tennis

 

2

4

T

Crickets

 

 

2

From the above table, Correct answer is option (A)

New answer posted

5 months ago

0 Follower 6 Views

A
alok kumar singh

Contributor-Level 10

Here, C3H6 is propene

   

Second reaction is iodoform reaction.

New answer posted

5 months ago

0 Follower 1 View

V
Vishal Baghel

Contributor-Level 10

Impurities present in electrolytic refining of blister Cu, removed as anode mud

= Sb, Se, Te, Ag, Au, Pt

Ans. = 6

New answer posted

5 months ago

0 Follower 4 Views

A
alok kumar singh

Contributor-Level 10

Given are the oxide of alkali and alkaline earth metals which are ionic in nature.

Simple oxide are Li2O, CaO, MgO and K2O.

Peroxide is Na2O2 and superoxide is KO2.

All simple oxides are diamagnetic as it has no unpaired electron.

New answer posted

5 months ago

0 Follower 4 Views

V
Vishal Baghel

Contributor-Level 10

log k = 20.35 - ( 2 . 4 7 * 1 0 3 ) T  

Comparing with,

l o g k = l o g A E a 2 . 3 0 3 R T

E a 2 . 3 0 3 R = 2 . 4 7 * 1 0 3

= 47.29 kJ/mole

Ans. = 47

New answer posted

5 months ago

0 Follower 5 Views

V
Vishal Baghel

Contributor-Level 10

  Δ T b = i K b m

m = w * 1 0 0 0 M * W s o l v e n t

For acetone solution,

0 . 1 7 = 1 * 1 . 7 * 1 . 2 2 * 1 0 0 0 M * 1 0 0

For Benzene solution,

2 A c i d ( A c i d ) 2 i = 1 / 2

Δ T b = i * K b * m

= 1 2 * 2 . 6 * 1 . 2 2 * 1 0 0 0 1 2 2 * 1 0 0 ° C

= 0 . 1 3 ° C = 1 3 * 1 0 2 ° C

x * 1 0 2 = 1 3 * 1 0 2

x = 1 3

New answer posted

5 months ago

0 Follower 2 Views

V
Vishal Baghel

Contributor-Level 10

Effective number of atom in C.C.P

= 1 8 * 8 + 1 2 * 6     

= 4

Number of octahedral void = 4

Number of cations = 4

Number of anion = 4

Formula of compound = A4B4

Empirical formula = AB

Ans. x = 1

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