Class 12th

(1) $N{a}^2{O}_2+2H_{2}O\to 2NaOH+H_2{O}_2$  

(2)  $Ba{O}_2.8H_{2}Ogives{H}_2{O}_2$ after evaporation

(3) PbO₂ + 2H₂O ->Pb (OH)₄

(4) SnO₂ + 2H₂O ->Sn (OH)₄

MnO -> Antiferromagnetism

O₂ -> Paramagnetism

NaCl -> Diamagnetism

Fe₃O₄ -> Ferrimagnetism

Tyndall effect is more effectively shown by lyophobic colloidal solution.

Type of back bonding:-

Therefore order of back bonding strength =>

BF₃ > BCl₃ > BBr₃ > Bl₃

The intermolecular association which is H-bonding is more prominent in case of primary amine as compared to secondary amines due to the availability of two hydrogen atom

V₂O₃ – Basic

CrO – Basic

Metal oxides are generally basic in nature but if more electronegative element are connected through central atom then deficiency of electron occurs on central atom and it behaves as acidic in nature.

Kindly consider the following figure

$cos{?}_1=\frac{R}{\sqrt[]{R^2+{\left(3R\right)}^2}}=\frac{1}{\sqrt[]{10}}$

$cos{?}_2=\frac{R}{\sqrt[]{R^2+{\left(3R-R\right)}^2}}=\frac{1}{\sqrt[]{2}}$

$\Rightarrow \frac{cos{?}_2}{cos{?}_1}=\frac{\sqrt[]{10}}{\sqrt[]{2}}=\sqrt[]{5}\Rightarrow x=1$

This is chloroform reaction.

B and C are tranquilizers