Class 12th
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5 months agoContributor-Level 10
Let us denote, the dozens of Bananas bought by A4's wife by a1, a2 by A3's wife, a3 by A2's wife and a4 by A1's wife. We prepare the table given below Bananas bought:
A1 = a4 A1's wife = a4
A2 = 2a3 A2's wife = a3
A3 = 3a2 A3's wife = a2
A4 = 4a1 A4's wife = a1
Where (a1, a2, a3, a4) is a rearrangement of (2, 3, 4, 5). Now, (a4 + 2a3 + 3a2 + 4a1) + (a4 + a3 + a2 + a1) = 44 4a1 + 3a2 + 2a3 + a4 = 44 – (2 + 3 + 4 + 5) = 30 …. (1) (Sum a1 + a2 +
New answer posted
5 months agoContributor-Level 10
Following are the possible ways from city Mumbai to city Lucknow.
I. Mumbai – Nagpur – Kolkata –Lucknow
II. Mumbai – Jammu – Orcha – Lucknow
III. Mumbai – Nagpur – Jammu – Orcha – Lucknow
The least possible number of cities is two.
New answer posted
5 months agoContributor-Level 10
A person can start and return the same city while passing through every city.
So, According to the given data option d is correct
New answer posted
5 months agoContributor-Level 10
The following are the possible ways:
I. Kolkata – Mumbai – Nagpur
II. Kolkata – Lucknow – Jammu – Nagpur – Mumbai
There are two possible ways.
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