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5 months ago

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V
Vishal Baghel

Contributor-Level 10

Let mass of water initially = x gram

Mass of sucrose = (1000 – x) gram

Mole of sucrose = 1 0 0 0 x 3 4 2 m o l

? 0.75 molal Þ 0.75 mole solute in 1 kg of solvent

0 . 7 5 = ( 1 0 0 0 x ) / 3 4 2 x / 1 0 0 0 [ m o l a l i t y = n s o l u t e M s o l v e n t ( k g ) ]

4 = ( 1 0 0 0 7 9 5 . 8 6 ) * 1 . 8 6 3 4 2 a        

a = 0.2775kg or 277.5 gram

Ice separated = (795.86 – 277.5) gram

= 518.3 gram

Ans. = 518 (the nearest integer)

New answer posted

5 months ago

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A
alok kumar singh

Contributor-Level 10

In the lyophilic colloids, the colloidal particles are extremely solvated.

New answer posted

5 months ago

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A
alok kumar singh

Contributor-Level 10

O 2 ( g ) U V O ( g ) + O ( g )  

O ( g ) + O 2 ( g ) U V O 3 ( g )      

Ozone in the stratosphere is a product of UV radiations acting on O2 molecule.

New answer posted

5 months ago

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V
Vishal Baghel

Contributor-Level 10

2 K 2 C r 2 O 7 + 8 H 2 S O 4 + 3 C 2 H 6 O 2 C r 2 ( S O 4 ) 3 + 3 C 2 H 4 O 2 + 2 K 2 S O 4 + 1 1 H 2 O

Given that, rate of appearance of Cr2(SO4)3 = + d [ C r 2 ( S O 4 ) 3 ] d t = 2 . 6 7 m o l e / m i n  

LHS                                                                 RHS

( R a t e o f d i s a p p e a r a n c e o f C 2 H 6 O 3 ) = ( R a t e o f a p p e a r a n c e o f C r 2 ( S O 4 ) 3 2 )            

Rate of disappearance of C2H6O = 2 . 6 7 * 3 2 m o l / m i n  

Rate of disappearance of C2H6O = 4.005 mol /min

Ans. = 4 (nearest integer)

New answer posted

5 months ago

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V
Vishal Baghel

Contributor-Level 10

Mass of organic compound = 0.2 gram

n A g B r = 0 . 1 8 8 1 8 8 m o l

= 0.001 mol

n B r = n A g B r = 0 . 0 0 1 m o l e

 Mass of Br = 0.001 * 80g

= 0.08 g

Mass & of Br = 0 . 0 8 0 . 2 * 1 0 0 %

= 40 %

New answer posted

5 months ago

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A
alok kumar singh

Contributor-Level 10

2 K M n O 4 Δ K 2 M n O 4 ( g r e e n ) + 6 + M n O 2 ( b l a c k ) + O 2

Mn6+ has one unpaired electron so paramagnetic and has green colour.

 

New answer posted

5 months ago

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V
Vishal Baghel

Contributor-Level 10

MCl3.2L => octahedral complex

M C l 3 . 2 L A g N O 3 ( e x c e s s ) 1 m o l e o f A g C l

It means one Cl- ion present in ionization sphere.

[ M C l 2 L 2 ] C l

For octahedral complex co-ordination numbers is 6

L is bidentate ligand i.e. its denticity is 2.

New answer posted

5 months ago

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A
alok kumar singh

Contributor-Level 10

Kindly go through the solution

 

New answer posted

5 months ago

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V
Vishal Baghel

Contributor-Level 10

Liquation is applicable for the refining of low melting point metals.

In liquation low melting point metal, melt at first and impurities take more time for melting therefore we can separate metal from their impurities.

New answer posted

5 months ago

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V
Vishal Baghel

Contributor-Level 10

FeCl3 + K4 [Fe (CN)6] (Potassium ferrocyanide)

excess

|

K Fe [Fe (CN)6]

(colloidal species)

Prussian Blue coloured 

colloidal complex

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