Class 12th

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New answer posted

8 months ago

0 Follower 2 Views

V
Vishal Baghel

Contributor-Level 10

Given I = 2r

μ 1 = 1 ( A i r )

μ 2 = 2 n

by, Snell's law

μ s i n i = μ 2 s i n r

i = 2 c o s 1 [ n 2 ]

New answer posted

8 months ago

0 Follower 13 Views

A
alok kumar singh

Contributor-Level 10

Kindly go through the solution

 

New answer posted

8 months ago

0 Follower 2 Views

V
Vishal Baghel

Contributor-Level 10

V 0 = 1 5 C

V 0 = C 5 , V S = 0

f = f 0 [ C + V 0 C + V s ]

V0 observer velocity

C sound velocity

Vs source velocity

= 6 5 f 0 f 0 f 0 * 1 0 0

= 1 5 * 1 0 0

% change in frequency = 20%

New answer posted

8 months ago

0 Follower 2 Views

A
alok kumar singh

Contributor-Level 10

M A 2 B 2 shows geometrical and not optical isomerism.

New answer posted

8 months ago

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V
Vishal Baghel

Contributor-Level 10

F = q E [ E = σ ε 0 ]

F = q σ 0 = 1 0 N

Final case – Now one plate is removed, Electric field will becomes half; So, force will become half.

F ' = 1 0 2 = 5 N

New answer posted

8 months ago

0 Follower 4 Views

V
Vishal Baghel

Contributor-Level 10

λ = h m v = h 2 M K . E

λ α 1 m

λ α m α = λ C 1 2 m C 1 2

λ α λ C 1 2 = m C 1 2 m α = 1 2 4 = 3 : 1

New answer posted

8 months ago

0 Follower 60 Views

A
alok kumar singh

Contributor-Level 10

Carbon-chlorine bond cleavage is not possible in C H 3 = C H - C l

New answer posted

8 months ago

0 Follower 6 Views

V
Vishal Baghel

Contributor-Level 10

Ultraviolet rays – sterilizing surgical instrument

Microwaves – Radar system

Infrared waves – Greenhouse effect

X-rays – Study crystal structure

New answer posted

8 months ago

0 Follower 14 Views

V
Vishal Baghel

Contributor-Level 10

Given, I = 5 sin (120πt), ω  = 120

T = 2 π ω

T = 2 π 1 2 0 π = 1 6 0 s e c , T 4 = 1 6 0 * 4 = 1 2 4 0 s e c

New answer posted

8 months ago

0 Follower 2 Views

A
alok kumar singh

Contributor-Level 10

Each ion makes a definite contribution irrespective of the other ion

Λ m 0 N a B r - Λ m 0 N a l = Λ m B r - 0 - Λ m r - 0 Λ m 0 K B r - Λ m 0 N a B r = Λ m K + 0 - Λ m N a + 0

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